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It is not possible to give a formula. This is because poyhedra are not unique shapes. For example, there are 257 topologically different convex octahedra!

A hexahedron (six faces) can be a triangular bipyramid (two triangular pyramids stuck base-to-base). This has only one diagonal in its interion. A hexahedron can also be a pentagon based pyramid which has 5 diagonals, on the surface of the base. Or it can be a cube (or variant) and that has 16 diagonals (12 on the faces and 4 in the interior). There are 4 more convex hexahedra topologically different from these.

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Q: What is the formula for the number of diagonals in a polyhedron?
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Related questions

What is the formula for the number of diagonals from a vertex?

Number of sides - 2


How does Euler's formula relate to the polyhedron?

The formula is V-E+F=2 and it tells us that if we take the number of vertices a polyhedron has and subtract the number of edges and then add the number of faces, that result will always be 2.


How many diagonals in triangle to dodecagon?

The formula is: 0.5*(n2-3n) = number of diagonals when n is the number of sides of the polygon


What is the formula to determine the number of diagonals in a polygon?

It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon


How do you get the total number of diagonals of a polygon?

The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon


What is the total number of diagonals?

Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon


What is the formula for the number of diagonals in a hexagon?

n side polygon has n(n-3)/2 diagonals therefore a hexagon has 9 diagonals


What is the formula for the sides of a polygon if the diagonals are given?

1/2*(n2-3n) = number of diagonals Rearranging the formula: n2-3n-(2*diagonals) = 0 Solve as a quadratic equation and taking the positive value of n as the number of sides.


How yo find the formula on how to solve the number of diagonals in a polygon?

It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon


What is the formula for the number of diagonals in a nonagon?

For a 9 sided polygon it is: 0.5*(92-(3*9)) = 27 diagonals


What is the formula to find the diagonals of a figure?

1/2*(n2-3n) = diagonals when n equals number of sides.


How do you find the number of sides of a polygon given the number of diagonals?

Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.