1/2*(n2-3n) = number of diagonals
Rearranging the formula: n2-3n-(2*diagonals) = 0
Solve as a quadratic equation and taking the positive value of n as the number of sides.
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
Using the formula: 0.5*(142-42) = 77 diagonals
It has 10 sides because using the formula 0.5*(102-30) = 35 diagonals
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
0.5*(n2-3n) where n is equal to the number of sides of the polygon
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
There is no such polygon that fits the given information.
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
Using the formula: 0.5*(142-42) = 77 diagonals
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
It has 10 sides because using the formula 0.5*(102-30) = 35 diagonals
0.5*(n2-3n) where n is equal to the number of sides of the polygon
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
By using the polygon diagonal formula or the quadratic equation formula in which in both formulae they work out that the polygon in question has 21 sides.
how many diagonals are there iin a polygon of 11 sides