The indefinite integral of (1/x^2)*dx is -1/x+C.
x/(x+1) = 1 - 1/(x + 1), so the antiderivative (or indefinite integral) is x + ln |x + 1| + C,
Integral of [1/(sin x cos x) dx] (substitute sin2 x + cos2 x for 1)= Integral of [(sin2 x + cos2 x)/(sin x cos x) dx]= Integral of [sin2 x/(sin x cos x) dx] + Integral of [cos2 x/(sin x cos x) dx]= Integral of (sin x/cos x dx) + Integral of (cos x/sin x dx)= Integral of tan x dx + Integral of cot x dx= ln |sec x| + ln |sin x| + C
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0.5
if you mean e to the x power times log of x, it is e to the x divided by x
1.001
-(x-1)-1 or -1/(x-1)
- ln ((x^2)-4)
∫ (1/x) dx = ln(x) + C C is the constant of integration.
If (x divided by 7) - 2 = 6, then x = 56 If x divided by (7 - 2) = 6, then x = 30
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