Using Pythagoras's theorem, you will find that the diagonal is sqrt(2) = 1.4142 cm (approx),
a≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm
The square's diagonal is 11.314 cm
The length of the diagonal of a square whose side lengths are 7 square root 2 (9.89949494) is: 14 units.
The diagonal of a 46' x 46' square is 65.05 feet.
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
Each side = sqrt (182 / 2) = sqrt (162) = 12.72792 metres
The length of the diagonal of any square whose sides are a whole number of units.
4
13 ft
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.
A Square
Use Pythagoras on the triangle formed by two adjacent sides and the diagonal between their other ends: diagonal = √(122 + 122) = 12 x √2 ~= 16.97 units