Wiki User
∙ 14y agoThe length of the diagonal of a square whose side lengths are 7 square root 2 (9.89949494) is: 14 units.
Wiki User
∙ 14y agoa≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm
The diagonal of a 46' x 46' square is 65.05 feet.
Using Pythagoras' theorem the length of the diagonal is 20 feet
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Firstly you need to work out the length of a side. Using Pythagorean Theorem for a right angled triangle a2+b2=c2 where a = the length, b = height & c = diagonal since c = 8 and a = b are the same 2a2 = 64 a2 = 32 a = 5.657 cm since the area of the square is a2 then area = 32cm2
The square's diagonal is 11.314 cm
14 because (7 square root of 2)squared then doubled is196 Square root of 196 is 14. There is trigonometry that shortens this.
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This is solved by pythagoras theorem: The longest length of a right angled triangle is equal to the square root of the sum of the other lengths squared. Therefore, 52 is 25, + 122 which is 144 = 169. The square root of 169 if i remember correctly is 13. So 13cm
Since the lengths on both sides of the square are the same the side length will be 6cm.
Easiest thing to do here would be to draw a diagram and label the sides with their lengths and draw a line for the diagonal. You can see the diagonal forms part of a right-angled triangle, with its shorter lengths 35 cm and 12 cm. So using Pythagoras's Theorem, x2 = 352 + 122 = 1369 x = square root of 1369 = 37 cm.
Using Pythagoras's theorem, you will find that the diagonal is sqrt(2) = 1.4142 cm (approx),
a≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
Using Pythagoras' theorem: 8 times the square root of 2 which is about 11,3137085 cm
Using Pythagoras, the length of the side can be calculated: Since it is a square, the two shorter lengths are the same, so: 2 x side2 = diagonal2 => side = sqrt(diagonal2 / 2) And once the side is known, the area can be calculated: area = side2 = diagonal2 / 2
Perimeter of a figure is the sum of its side lengths. In a square, all four sides are the same length. So, the perimeter of a square whose side length is 8.5 is 4 x 8.5 = 34.