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Each number in this sequence is twice the previous number. The nth. term is 2n-1.

Each number in this sequence is twice the previous number. The nth. term is 2n-1.

Each number in this sequence is twice the previous number. The nth. term is 2n-1.

Each number in this sequence is twice the previous number. The nth. term is 2n-1.

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Q: What is the nth term of 1 2 4 8?

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The nth term is 2n

1...2....3....43...7...11..157 - 3 = 411 - 7 = 415 - 11 = 4(the start of the nth term is 4n)4 x 1 = 4(but the first term is 3, so...)4 -1 = 3nth term = 4n - 1

1 4 9 is a series of squared numbers. The nth term is [ n squared ]

1254

3n-2

3n-2

It is: nth term = 6n-4

The nth term is: 3n-7 and so the next number will be 11

The nth term is: 3n-7 and so the next number will be 11

n - 1

You can see that you add 10 to the previous term to get the next term. Term number 1 2 3 4 Term 4 14 24 34 You can also say: Term number 1 2 3 4 Term 0*10+4 1*10+4 2*10+4 3*10+4 So the nth term would be 10(n-1)+4 Or if you expand it, it's 10n-6

The Nth term in the series is [ 2N ] .

11

The nth term of the sequence is 3n - 2.

The nth term of the series is [ 4/2(n-1) ].

The nth term would be -2n+14 nth terms: 1 2 3 4 Sequence:12 10 8 6 This sequence has a difference of -2 Therefore it would become -2n. Replace n with 1 and you would get -2. To get to the first term you have to add 14. Therefore the sequence becomes -2n+14. To check your answer replace n with 2, 3 or 4. You will still obtain the number in the sequence that corresponds to the nth term. :)

the nth term for 1 2 4 8 16 32 is 2 to the power n-1. I cannot type superscript. It look like a big 2 and then n-1 where we put small number on the top right hand.

The nth term is (2n - 12).

n^2 + 2n + 1

They are: nth term = 6n-4 and the 14th term is 80

If you mean: 3, 4, 5, 6 and 7 then nth term = n+2

The nth term is: 3n+1 and so the next number will be 16

This is an Arithmetic Series/Sequence. In general the nth term, A(n) = a + (n - 1)d....where a is the 1st term and d is the common difference. In this question, the 1st term equals 1 and the common difference is 4. Then the nth term, A(n) = 1 + (n - 1) x 4 = 1 + 4n - 4 = 4n - 3.

If you mean: 2 4 8 16 32 64 it is 2^nth term and so the next number is 128

The next term is: 15+4 = 19 The nth term is: 4n-5

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