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What is the nth term of the arithmetic sequence of 6 12 18 24..?
Wiki User
∙ 6y ago
The nth term of an AP with initial term a (= u{1}) and common difference d is given by:
u{n} = a + (n - 1)d
In this case:
a = 6
d = (12 - 6) = 6
→ u{n} = 6 + (n - 1)6
But this can be simplified:
u{n} = 6 + (n - 1)6
= 6 + 6n - 6
= 6n
Wiki User
∙ 6y ago
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