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The nth term of an AP with initial term a (= u{1}) and common difference d is given by:

u{n} = a + (n - 1)d

In this case:

a = 6

d = (12 - 6) = 6

→ u{n} = 6 + (n - 1)6

But this can be simplified:

u{n} = 6 + (n - 1)6

= 6 + 6n - 6

= 6n

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โˆ™ 2017-07-02 07:55:13
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Q: What is the nth term of the arithmetic sequence of 6 12 18 24..?
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