Top Answer

What is the product of y and 10

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8🤨

6😮

3😂

410 + y

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6🤨

14😮

8😂

6Loading...

9y

17

x = 10, y = 25

1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.

Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3

The sum of x and y decreased by their product is (x + y)- xy.

Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2

y - intercept = 10x - intercept = -10y- intercept: x = 0y = x + 10y = 0 + 10y = 10x - intercept: y = 0y = x + 100 = x + 10x + 10 = 0x = -10

If: 30y = 10+y Then: y = 10/29

the product is y=5sindn

20

The Y intercept of y=7x+10 is 10.

y is 2 less than the product of 3 and x

You can set this up as follows... Let the two numbers be defined as x and y. Then, x * y = 96 x - y = 10 x = 96/y and substitute 96/y - y = 10 rearranging yields a quadratic equation 96 - y^2 = 10y or y^2 + 10y - 96 = 0 The solution(s) to the quadratic equation are given by: y = (-b +/- sqrt(b^2-4ac)) / 2a y = (-10 +/- sqrt(100 - 4(-96))) / 2 y = (-10 + 22 ) / 2 = 6 y = (-10 - 22 ) / 2 = -16 So, y can be 6 or -16 making x = 16 or -6 So you have two answers, (x,y) = (16,6) or (x,y) = (-6,-16)

It is meaningless. You need at least two numbers to get a product. E.g., the product of x and y is xy (x times y).

10 + y = 4y = 4 - 10 y = -6

6x = 10-y y = -6x+10 The slope is -6 and the y intercept is 10

The oroduct of 'y' and '8' is 8y

(x+y)/2

Yes. You must solve the two simultaneous equations below: x * y = 18 x - y = 10 When you do so, you will get two solution sets: x = 11.557 (approx.) y = 1.557 (approx.) and x = -1.557 (approx.) y = -11.557 (approx.)

6y

4y+y=10 5y=10 y=2

x+y does not equal 10, which can be written x+y ~= 10 or x+y != 10.

The formula is: y/-10 = 12 Multiplying both sides by -10 gives, y * -10/-10 = 12 * -10 Thus y = -120

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