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y=2x-6

Q: What is the slope-intercept form of a line that has a slope of 2 and contains the points 4 2?

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Points: (-5, 9) and (-4, 7) Slope: -2 Equation: y = -2x-1 in slope intercept form

y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0

y = -3x + 5

Equation of the straight line: y = -3/5x+2 in slope intercept form

You need two points before you can calculate the slope.

Related questions

y = 2x + 1.

Points: (-5, 9) and (-4, 7) Slope: -2 Equation: y = -2x-1 in slope intercept form

y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0

Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14

y = -3x + 5

Points: (0, 5) and (5, 8)Slope: 3/5Equation: y = 3/5x+5 in slope intercept form

Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

Equation of the straight line: y = -3/5x+2 in slope intercept form

point slope form is y-y1=m(x-x1). x1 and y1 are both points and m is the slope.

You need two points before you can calculate the slope.

The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3

Points: (4, 9) Slope:3 Equation:- y-9 = 3(x-4) y = 3x-12+9 y = 3x-3 in slope intercept form