112357 Note, these are not in order, which is probably the trick to the question.
The smallest number divisible by first four prime numbers is 2x3x5x7 = 210.
2 is the smallest prime number.
The first prime numbers are 2, 3, 5, 7, 11. When multiplied together the product is 2310. It is the smallest number that has the first five numbers as its factors.
Just multiply the first five prime numbers! 2x3x5x7x11 = 6x35x11 = 210x11 = 2310. Any multiple of this number "has the first five prime numbers as factors", but 2310 is the smallest such number.
The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).
120
multiply these prime numbers together to get your answer
2310
The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.
27720
the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.
120