Two possible interpretations of this question.
Let the 3 consecutive odd numbers be a, a + 2 and a + 4.
1) a + (a + 4) = [3 x (a + 2)] - 11
2a + 4 = 3a + 6 - 11 : a = 9
The 3 numbers are 9,11 & 13
This gives 9 + 13 = 22 and (3 x 11) - 11 = 22.
2) a + (a + 4) = 3 x (a + 2 -11)
2a + 4 = 3a - 27 : a = 31
The 3 numbers are 31, 33 & 35
This gives 31 + 35 = 66 and 3 x (33 -11) = 3 x 22 = 66.
They are 14, 16 and 18.
The let statement is: let the smallest of the three integers be x.
Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.
There are no such consecutive integer as is so simple to prove! Suppose the first integer is x. Then the next (consecutive) integer is x+1. Then 2*x + 4*(x+1) = 30 So that 2x + 4x + 4 = 30 6x + 4 = 30 6x = 30 - 4 = 26 x = 26/6 which is NOT an integer.
9, 11, and 139 + 2(11) + 3(13) = 9 + 22 + 39 = 70
51
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
They are 14, 16 and 18.
10-11-12
The numbers are 14, 16 and 18.
The let statement is: let the smallest of the three integers be x.
Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.
The second integer is 51.The integers are 50, 51, and 52, so therefore the second integer is 51. This problem can be solved using this method:(x) + (x+1) + (x+2) = 1533x + 3 = 1533x = 150x = 50If x = 50, then (x+1) = 51, and (x+2) = 52.
There are no such consecutive integer as is so simple to prove! Suppose the first integer is x. Then the next (consecutive) integer is x+1. Then 2*x + 4*(x+1) = 30 So that 2x + 4x + 4 = 30 6x + 4 = 30 6x = 30 - 4 = 26 x = 26/6 which is NOT an integer.
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
9, 11, and 139 + 2(11) + 3(13) = 9 + 22 + 39 = 70