0
Find three consecutive odd integers such that the sum of the first integer twice the second integer and three times the third is 70?
Wiki User
∙ 13y ago
9, 11, and 13
9 + 2(11) + 3(13) = 9 + 22 + 39 = 70
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
The sum of 3 consecutive even integers is 54 What is the first consecutive integer?
The first integer is 17.
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?
The let statement is: let the smallest of the three integers be x.
What is the equation for this The sum of two consecutive integers in 71?
Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.
When you double the first and quadruple the second integer their sum is 30 find the consecutive integers?
There are no such consecutive integer as is so simple to prove! Suppose the first integer is x. Then the next (consecutive) integer is x+1. Then 2*x + 4*(x+1) = 30 So that 2x + 4x + 4 = 30 6x + 4 = 30 6x = 30 - 4 = 26 x = 26/6 which is NOT an integer.
The sum of 3 consecutive even integers is 54 What is the first consecutive integer?
The first integer is 17.
The sum of 4 consecutive integers is 182 What is the first integer?
The first integer is 44.
Find four consecutive integers such that the sum of the second and fourth is 132 show the work?
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
How Find three consecutive even integers such that three times the first integer i six more than twice the second integer?
They are 14, 16 and 18.
What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?
The numbers are 14, 16 and 18.
FIND Three consecutive integers such that the sum of the second and the third is 17 Which equation would be used to solve this word problem?
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?
The let statement is: let the smallest of the three integers be x.
What is the equation for this The sum of two consecutive integers in 71?
Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.
When you double the first and quadruple the second integer their sum is 30 find the consecutive integers?
There are no such consecutive integer as is so simple to prove! Suppose the first integer is x. Then the next (consecutive) integer is x+1. Then 2*x + 4*(x+1) = 30 So that 2x + 4x + 4 = 30 6x + 4 = 30 6x = 30 - 4 = 26 x = 26/6 which is NOT an integer.
Find 2 consecutive integers whose difference is 2?
no solution. If you solve for x (where x is the first integer) the answer is a fraction, which is not an integer.
What is the sum of four consecutive even integers is 2 more than five times the first integer?
The integers would begin with 10.
