The points are (2,5) and (4,9)
We can find the slope of the line between those points easily.
It is (9-5)/(4-2)=4/2=2
Now use point slope form.
y-5=2(x-2)
or you can use the other point
y-9=2(x-4)
You get the same answer either way
y=2x+5-4=2x+1
So y=2x+1
Using the other equation
y=2x-8+9 so once again
y=2x+1
A good way to check that you did not make an error is to plug in the point.
5=2(2)+1.. YES that works
and
9=2(4)+1, YES that works too.
Our work is done here.
The Slope of a line containing the points (2,2) and (4,2) is Y=0
It is a straight line with no slope with a 'y' intercept of 2
y=2x-6
The line will have the same slope but a different y intercept
Points: (-5, 9) and (-4, 7) Slope: -2 Equation: y = -2x-1 in slope intercept form
The Slope of a line containing the points (2,2) and (4,2) is Y=0
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
Points: (4, -2) and (6, -3) Slope: -1/2 Straight line equation: y = -1/2x There is no y intercept.
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
If you mean a slope of 4 and points of (0, 2) then the equation is y = 4x+2.
It is a straight line with no slope with a 'y' intercept of 2
a line passes through the points (-10 -4) and (-1 2). what is the y-intercept of the line
you put the y intercept at 2, the x intercept at -2/3 and you join those two points.
What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x
y=2x-6
Points: (2, 0) and (0, -6) Slope: 3 Equation: y = 3x -6
The line will have the same slope but a different y intercept