Use the formula: y - y1 = m(x - x1)
y = -3x +7
Alternatively, from the problem statement, the equation must have the form y = -3x + c, where c is a temporarily unknown constant. From the second part of the problem statement, -5 = (-3)(4) + c, or - 5 = -12 + c, or c = 12 - 5 = 7. Therefore the required equation is y = -3x + 7, -3 is the slope, and 7 is the y-intercept.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
It is: y-7 = 2(x-3) => y = 2x+1
As a straight line equation: y = -3x+18 in slope intercept form
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
y = 2x + 1.
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
The answe iss..... 6
y = 2x - 1
y=2x+1
It is: y = 2x-6
The equation is (y - 1) = 2(x - 1) or, y = 2x - 1
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Choose the equation of the line that contains the points (1, -1) and (2, -2).
It is: y-7 = 2(x-3) => y = 2x+1