Best Answer

Use the slope intercept form here,

Y - Y1 = m(X - X1)

m = 2

Y1 and X1 = (3, 7)

(Y - 7) = 2(X - 3)

Y - 7 = 2X - 6

Y = 2X + 1

----------------the equation of the line

Q: Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point 3 7?

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y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0

The equation is (y - 1) = 2(x - 1) or, y = 2x - 1

It is: y-7 = 2(x-3) => y = 2x+1

As a straight line equation: y = -3x+18 in slope intercept form

If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33

Related questions

y = 2x + 1.

y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0

The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3

Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

y = 2x - 1

y=2x+1

The answe iss..... 6

It is: y = 2x-6

The equation is (y - 1) = 2(x - 1) or, y = 2x - 1

if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form

Choose the equation of the line that contains the points (1, -1) and (2, -2).

As a straight line equation: y = -3x+18 in slope intercept form