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So the roots are -1 and 7
(x-7)(x+i)(x-i)
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∙ 11y ago
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What are the factors of 5x2-13x?
5x^2 - 13x = x(5x - 13)
Find the factors of x3-5x2 8x-4 how to solve this equation?
5x2-8x-4
How do you factor x3 plus 5x2 minus 16x minus 80?
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
X3 - 14x2 plus 13x?
x(x - 13)(x - 1)
What is the factorization of this trinomial x3 plus 13x2 plus 42x?
x3 + 13x2 + 42x = x(x2 + 13x + 42) = x(x2 + 6x + 7x + 42) = x[x(x + 6) + 7(x + 6)] = x(x + 7)(x + 6)
2x3 - 7 plus 5x2 - x3 plus 3x - x3?
2x3 - 7 + 5x - x3 + 3x - x3 = 8x - 7
What are the factors of 5x2-13x?
5x^2 - 13x = x(5x - 13)
how do i solve this 5x2 + 3x2 – x3 + 2x3 + 10x4 – 5x4?
x2 • (5x2 + x + 8)
Find the factors of x3-5x2 8x-4 how to solve this equation?
5x2-8x-4
How do you factor x3 plus 5x2 minus 16x minus 80?
To factorise x3 + 5x2 - 16x - 80 I note that -80 = 5 x -16 and 5 & -16 are the coefficients of x2 and x. Thus I have: x3 + 5x2 - 16x - 80 = (x + 5)(x2 - 16) and the second term is a difference of 2 squares, meaning I have: x3 + 5x2 - 16x - 80 = (x + 5)(x + 4)(x - 4)
Factor the polynomial of x3 plus 5x2 - x - 5?
x3 + 5x2 - x - 5 = (x2 - 1)(x + 5) = (x + 1)(x - 1)(x + 5)
X3 - 14x2 plus 13x?
x(x - 13)(x - 1)
What is the factorization of the trinomial x3-14x2 13x?
x(x - 1)(x - 13)
How do you factor x3 - 14x2 plus 13x?
x(x - 13)(x - 1)
What is the factorization of this trinomial x3 plus 13x2 plus 42x?
x3 + 13x2 + 42x = x(x2 + 13x + 42) = x(x2 + 6x + 7x + 42) = x[x(x + 6) + 7(x + 6)] = x(x + 7)(x + 6)
How do you factor 2x2 - 13x - 7?
2x2 - 13x - 7 = (2x + 1)(x - 7)
What is 3x 25x-7?
13x-14 or 13x+(-14)
