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You roll a pair of dice until you get doubles What is the probability that you get doubles in three or fewer rolls?
Wiki User
∙ 8y ago
!
So first of all we need to calculate the probability of the base event, that is to get a pair when rolling 2 dice.
This is quite simple and we can see it in 2 ways.
a) We throw the first dice, regardless of what it comes up as, we have 1 in 6 chanses that the second dice matches it i.e probability = 1/6
b) There are 6*6 possible out comes when rolling two dice. Out of those we can get pair of 1s, pair of 2s , pair of 3s, pair of 4s, pair of 5s or pair of 6s. That is 6 pairs out of 36 total = 1/6 probability.
Now about making a sequence of throws.
The probability of us making the pair in the first throw is as the basic event = 1/6.
If we make it we dont continue and have reached our goal!
If we dont get a pair (proability 1-1/6 = 5/6) we continue and make our second throw. Again we have a 1/6 chanse, so in total that we make it in exactly the 2nd throws is 5/6 (miss)*1/6 (hit) = 5/36.
If we dont make it , we continue again. Now our chance in making it in exactly the 3rd time is 5/6 (miss)*5/6 (miss again) *1/6 (hit) = 25/216.
So the probability of making a pair in three or fewer rolls is the sum of the above, so 1/6 + 5/36 + 25/216 = 91/216 = 0.42 (roughly)
Another way when you have established the probability of a single action to find how many repeats you need is to use the Binomial or Poisson distribution (look it up).
Best Regards
Wiki User
∙ 8y ago
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What is the probability of throwing a sum of 15 on three rolls of a fair die if the first roll was a 4?
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
What is the probability that none of the rolls is a six?
It depends on what size die you use, what its labels are and how many rolls you make. For example using a standard six-sided die and one roll, the probability of no sixes is 5/6 or ~0.83; the probability of no sixes with 25 rolls is less than 0.01 or 1%. If you used a standard d3 (three-sided die) then the probability will always be 1 or 100%, since rolling a six is impossible; but if every side has '6' on it the probability is 0, since every roll must be a 6.
What is the probability that 6 rolls of a fair die will show exactly three fives?
The probability of getting three fives in the first three rolls and non-fives in the next three rolls is; P(5,5,5,N5,N5,N5) = 1/6 x 1/6 x 1/6 x 5/6 x 5/6 x 5/6 = 0.002679... The number of different order in which the fives can come out is given by; 6C3 = 6!/[3!∙(6-3)!] = 20 So the probability that in 6 rolls of a fair die exactly three fives (in any order) will come out is; P(three fives any order) = (20)∙(1/6)3∙(5/6)3 = 0.05358... ~ 5.4%
A dice is rolled three times the probability of getting at least one odd number is?
Possible outcomes of one roll = 6.Probability of an even number on one roll = 3/6 = 0.5 .Probability of an even number on the second roll = 0.5 .Probability of an even number on the third roll = 0.5 .Probability of an even number on all three rolls = (0.5 x 0.5 x 0.5) = 0.125 = 1/8The probability of at least one odd number is the probability of not gettingan even number on all 3 rolls. That's (1 - 1/8) = 7/8 or 0.875 or 87.5% .
What is the probability of rolling doubles greater than three?
In the case of dice, greater than three, means 4,5 or 6. So, obviously, three cases out of 36.
What is the probability of rollling a 5 3times ina row?
With a fair die, it is 1/216 in three rolls, but the probability increases to 1 (a certainty) as the number of rolls is increased.
What is the probability that 12 rolls of a fair die will show three ones?
It is approx 0.1974
What is the probability of rolling exactly one 4 in three rolls of a dice?
3/18 I think
How do you get the probability of three dice rolls?
The probability of 3 specific dice rolls is the probability that each one will happen multiplied together. For instance, the probability of rolling 2 then 6 then 4 is the probability of all of these multiplied together: The probability of rolling 2 is 1/6. The probability of rolling 6 is 1/6. The probability of rolling 4 is 1/6. Multiply these together and we get the total probability as 1/216
What is the probability of getting three fives in three rolls of a single die?
Anywhere from 0 to 1; it depends on the shape and what numbers are written on the faces.
What is the probability of getting three or fewer heads on eight tosses of a coin?
It is 93/256 = 0.363 approx.
What is the probability of throwing a sum of 15 on three rolls of a fair die if the first roll was a 4?
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
What is the probability that none of the rolls is a six?
It depends on what size die you use, what its labels are and how many rolls you make. For example using a standard six-sided die and one roll, the probability of no sixes is 5/6 or ~0.83; the probability of no sixes with 25 rolls is less than 0.01 or 1%. If you used a standard d3 (three-sided die) then the probability will always be 1 or 100%, since rolling a six is impossible; but if every side has '6' on it the probability is 0, since every roll must be a 6.
You roll six sided die three timeswhat is the probability that all three rolls will be a 1?
The probability that each roll will be a 1, is 1/6 (a sixth) because there is one outcome of interest (getting a 1) and 6 possible outcomes (6 numbers on the die).Probability rules mean that if you want the probability of getting outcome A and getting outcome B then the total probability is P(A) x P(B) where P(A) means the probability of getting outcome A).In short if you want P(A and B) then this is P(A) x P(B)Applied to this example if you want the probability of getting a 1 on each throw of the die (i.e. on all 3 throws) then the probability is given by:P(1 on all three rolls) = P(1 on first roll) x P(1 on second role) x P(1 on third role)P(1 on all three rolls) = 1/6 x 1/6 x 1/6P(1 on all three rolls) = 1 / 216
What is the probability that 6 rolls of a fair die will show exactly three fives?
The probability of getting three fives in the first three rolls and non-fives in the next three rolls is; P(5,5,5,N5,N5,N5) = 1/6 x 1/6 x 1/6 x 5/6 x 5/6 x 5/6 = 0.002679... The number of different order in which the fives can come out is given by; 6C3 = 6!/[3!∙(6-3)!] = 20 So the probability that in 6 rolls of a fair die exactly three fives (in any order) will come out is; P(three fives any order) = (20)∙(1/6)3∙(5/6)3 = 0.05358... ~ 5.4%
What is the probability of rolling 6 and four in backgammon three times in a row?
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
A dice is rolled three times the probability of getting at least one odd number is?
Possible outcomes of one roll = 6.Probability of an even number on one roll = 3/6 = 0.5 .Probability of an even number on the second roll = 0.5 .Probability of an even number on the third roll = 0.5 .Probability of an even number on all three rolls = (0.5 x 0.5 x 0.5) = 0.125 = 1/8The probability of at least one odd number is the probability of not gettingan even number on all 3 rolls. That's (1 - 1/8) = 7/8 or 0.875 or 87.5% .
