0
{2+(2x-y)-(3x-y)
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How do you solve y equals y equals 2x-1 y equals 5x-13?
y = 2x -1 y = 5x -13 So: 5x -13 = 2x -1 5x -2x = 13 -1 3x = 12 x = 4 and by substituting y = 7
2x plus 3y equals 13 3x minus y equals 3 x equals?
2x+3y=13 3x-y=3 x=2
X plus y equals 2 and y equals 2x-13?
1. x + y = 22. y = 2x - 13Rewriting 2. as:3. 2x - y = 13Adding 1 & 3 gives:4. 3x = 15x = 5Substituting x = 5 into 1. gives:5 + y = 2y = 2 - 5y = -3Checking values by substituting x = 5 and y = -3 into 2 gives:-3 = (2 * 5) - 13-3 = 10 - 13-3 = -3Therefore x = 5 and y = -3.
What is the x-intercept of 2x-y-2?
So, is that to say that 2x-y-2 = 0? Taking into consideration that y = mx + b ... 2x-2 = y y = 2x -2 In y = mx + b, the "b" is the y intercept the "m" is the slope To find the x intercept, make y = 0 and solve. 0 = 2x -2 2 = 2x x = 1
How do you factor 20x2 plus 22xy plus 6y2?
20x2 + 22xy + 6y2 = 20x2 + 10xy + 12xy + 6y2 = 10x(2x + y) + 6y(2x + y) = (2x + y)(10x + 6y) = 2(2x + y)(5x + 3y)
What is the sum of 2x divided by y-2 and 2x divided by 2-y?
2x / (y-2) + 2x / (2-y)First get a common denominator: (y-2) (2-y)Then you have:2x(2-y) / (y-2)(2-y) + 2x(y-2) / (y-2)(2-y), summing and simplifying, you get:(4x-4) / (y-2)(2-y)
How do you solve y equals y equals 2x-1 y equals 5x-13?
y = 2x -1 y = 5x -13 So: 5x -13 = 2x -1 5x -2x = 13 -1 3x = 12 x = 4 and by substituting y = 7
What is the derivative of y equals 2x TIMES 2x?
y=(2x)2 y=2(2x) y=4x
What are the values of x and y which satisfy the equations x plus 2y equals 27 and 2x minus y equals 19?
x + 2y = 27 2x - y = 19 y = 2x - 19 x + 2(2x - 19) = 27 x + 4x - 38 = 27 5x = 65 x = 13 y = 2(13) - 19 y = 7
2x plus 5y equals 2 -3x - y equals -2?
Those would be two equations that each describe a different line: 2x + 5y = 2 -3x - y = -2 If you'd like to find the point at which they intersect, that can be done using the substitution method. First, take either of the equations and solve it for one of the two variables. In this case, we'll solve the second equation for y: -3x - y = -2 ∴ y = 2 - 3x Now take that definition of y, and plug it into the other equation: 2x + 5y = 2 ∴ 2x + 5(2 - 3x) = 2 ∴ 2x + 10 - 15x = 2 ∴ -13x = -8 ∴ x = 8/13 Now you can take that value of x, and plug it into either of the original equations to find the value of y: 2x + 5y = 2 ∴ 16/13 + 5y = 2 ∴ 5y = 26/13 - 16/13 ∴ 5y = 10/13 ∴ y = 2/13 To be certain that our answer is correct, we should also plug that value into the other original equation: -3x - y = -2 ∴ -24/13 - y = -2 ∴ -y = -26/13 + 24/13 ∴ y = 2/13 So our answer is indeed correct, and the two lines intersect at the point (8/13, 2/13)
2x plus 3y equals 13 3x minus y equals 3 x equals?
2x+3y=13 3x-y=3 x=2
How do you solve for y if -2x plus 13y equals 11?
-2x+13y=11 13y=2x+11 y=2x/13 + 11/13
X plus y equals 2 and y equals 2x-13?
1. x + y = 22. y = 2x - 13Rewriting 2. as:3. 2x - y = 13Adding 1 & 3 gives:4. 3x = 15x = 5Substituting x = 5 into 1. gives:5 + y = 2y = 2 - 5y = -3Checking values by substituting x = 5 and y = -3 into 2 gives:-3 = (2 * 5) - 13-3 = 10 - 13-3 = -3Therefore x = 5 and y = -3.
What is the answer to Y equals 2X plus 6 2X-Y equals 2?
eqn 1 Y = 2X + 6 eqn 2 2X - Y = 2 Rearrange eqn2 to isolate Y eqn2 Y = 2X - 2 so 2X + 6 = 2X - 2 subtracting 2X from both sides we get 6 = -2 As this is impossible this set of equations can not be solved.
How do you solve 2x y 4?
Solve for y: f(-5)=13+2x
What is the solution to the system 2x-y equals 2 2x-y equals -2?
2x - y = 2 2x - y = -2 This system is inconsistent -- that is, there is no solution. To help see why, let Z = 2x - y and notice Z can't be 2 and -2 at the same time.
What is the x-intercept of 2x-y-2?
So, is that to say that 2x-y-2 = 0? Taking into consideration that y = mx + b ... 2x-2 = y y = 2x -2 In y = mx + b, the "b" is the y intercept the "m" is the slope To find the x intercept, make y = 0 and solve. 0 = 2x -2 2 = 2x x = 1
