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{2+(2x-y)-(3x-y)
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How do you solve y equals y equals 2x-1 y equals 5x-13?
y = 2x -1 y = 5x -13 So: 5x -13 = 2x -1 5x -2x = 13 -1 3x = 12 x = 4 and by substituting y = 7
2x plus 3y equals 13 3x minus y equals 3 x equals?
2x+3y=13 3x-y=3 x=2
X plus y equals 2 and y equals 2x-13?
1. x + y = 22. y = 2x - 13Rewriting 2. as:3. 2x - y = 13Adding 1 & 3 gives:4. 3x = 15x = 5Substituting x = 5 into 1. gives:5 + y = 2y = 2 - 5y = -3Checking values by substituting x = 5 and y = -3 into 2 gives:-3 = (2 * 5) - 13-3 = 10 - 13-3 = -3Therefore x = 5 and y = -3.
What is the x-intercept of 2x-y-2?
So, is that to say that 2x-y-2 = 0? Taking into consideration that y = mx + b ... 2x-2 = y y = 2x -2 In y = mx + b, the "b" is the y intercept the "m" is the slope To find the x intercept, make y = 0 and solve. 0 = 2x -2 2 = 2x x = 1
How do you factor 20x2 plus 22xy plus 6y2?
20x2 + 22xy + 6y2 = 20x2 + 10xy + 12xy + 6y2 = 10x(2x + y) + 6y(2x + y) = (2x + y)(10x + 6y) = 2(2x + y)(5x + 3y)
