-2x(x + 3)(x + 2)
-2x(x + 3)(x + 2)
Do you want its factorisation? 2x3 + 2x2 - 12x = 2x(x2 + x - 6) = 2x(x + 3)(x - 2).
-2x3 + 2x2 + 12x =(-2x) (x2 - x - 6) =(-2x) (x+2) (x-3)
I assume your problem is: -2x3-2x2+12x-2x(x2-x-6)-2x(x-3)(x+2)
(-2x3 - 2x2 + 12x) = -2x (x2 + x - 6) = -2x (x + 3) (x - 2)
whats the answer for -2x^3+2^2+12x
-2x(x + 3)(x + 2)
-2x(x + 3)(x - 2)
-2x3 - 2x2 + 12x = -2x(x2 + x - 6) = -2x(x2 - 2x + 3x - 6) = -2x[ x(x - 2) + 3(x - 2) ] = -2x(x + 3)(x - 2)
-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)
-2x3-2x2+12x (-2)(x3+x2-6x) (-2x)(x2+x-6) (-2x)(x2+3x-2x-6) (-2x)((x)(x+3)-2(x+3)) (-2x)((x-2)(x+3)
Factor out -2x since that is the GCD of the terms, so we obtain: -2x(x² + 5x + 6) By decomposition, we have: -2x(x² + 3x + 2x + 6) Factor-by-grouping, we obtain: -2x(x(x + 3) + 2(x + 3)) = -2x(x + 2)(x + 3) [Collect the terms and group the binomials]