First, draw a picture.
Draw a horizontal line that represents the ground, and another perpendicular line to it that represents the tree. Denote with B the point of the intersections of these two lines, and with C the point on the perpendicular line which is 15 ft far from the ground. So the angle B is 90 degrees. The sun will be on the right side of BC. From the point C draw a straight line in the direction of the sun, which cuts the horizontal line at the point A. So, the angle of elevation of the sun is the angle A.
A right triangle is formed, the triangle ABC, where the side opposite to angle A is 15 ft, and the adjacent side is 8 ft, so
tan A = opposite/adjacent = 15/8
So, the measure of angle A = arctan (15/8) = 62 degrees.
Angle of elevation: tan-1(100/130) = 37.6 degrees rounded to one decimal place
tan(A) = 120/100 =39.81 degrees
51.34019175 degrees or as 51o20'24.69''
The answer rounded to the nearest tenth is 25 meters.
You can measure it. Or you can measure some other quantities (for examples, the lengths of the sides of a triangle), and calculate the angle using trigonometry.
36 degrees
Using trigonometry the angle of elevation is 77 degrees rounded to the nearest degree
Tan60= 25/Height. Height = 25/Tan60 = 14.43
If you mean the height of the building then it works out as 466.5063509 feet
If you also know its shadow then you can work out the angle of elevation
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
The angle would be .4 if you rounded it to the nearest 10th degree
sin-1(1/20) = 3 degrees.
Use the tangent ratio: 23*tan(23) = 9.762920773 Answer: 10 meters to the nearest meter
51
To find the angle of elevation of a rod given the ratio of its height to the length of its shadow as (1 : \sqrt{3}), we can use the tangent function. The tangent of the angle of elevation ( \theta ) is equal to the ratio of the opposite side (height of the rod) to the adjacent side (length of the shadow). Therefore, ( \tan(\theta) = \frac{1}{\sqrt{3}} ). This corresponds to an angle of ( 30^\circ ).
Using trigonometery if you know the length of its shadow and angle of elevation