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yes they are because 4x is the same as x multiplied by 4 which is not the same as x-2

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Q: Are x-2 and 4x different equations?
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Related questions

What is 4x-x2?

4x-x2 = 2


Can you complete the square factor and use the quadratic formula to solve these two equations x2-4x-21 equals 0 and x2-3x-18 equals 0?

x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6


What is X2 divided by -4x?

6


What are the factors of x2 - 4x?

-2


Factor x2 - 4x - 32?

x2 - 4x - 32 = (x - 8)(x + 4)


Is x2 - 4x -12 prim?

No. x2 -4x - 12 = (x + 2)(x - 6)


Solve x2 - 4x - 9 equals 0 by completing the square?

x2 - 4x - 9 = 0 ∴ x2 - 4x = 9 ∴ x2 - 4x + 4 = 13 ∴ (x - 2)2 = 13 ∴ x - 2 = ±√13 ∴ x = 2 ± √13


Factor x2 plus 4x plus 6?

x2 + 4x + 6 can not be factored. If you want, you can reduce it to an expression with a single x term by comleting the square: x2 + 4x + 6 = x2 + 4x + 4 + 2 = (x + 2)2 + 2


What is x2 plus 4x plus 4 equals 25?

x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3


X2 plus 1 divided by 2x4 plus 4x3 -x2 plus 4x-3?

You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)


What is a common factor of x2-16 and x2-4x?

x2 - 4


How do you factor x2 plus 4x-96?

x2 + 4x - 96 = (x - 8)(x + 12).