Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
130 is the area.
If you want to find the area of a rectangle (inclusively a square), rhombus, or parallelogram, you multiply.
An octagon is a non-rigid shape. In the same way that a square can be flexed into a rhombus and reduce the area by making the rhombus thinner, an octagon can be flexed into a shape with as small an area as you like.Its maximum area is 482.8 cm2(approx).An octagon is a non-rigid shape. In the same way that a square can be flexed into a rhombus and reduce the area by making the rhombus thinner, an octagon can be flexed into a shape with as small an area as you like.Its maximum area is 482.8 cm2(approx).An octagon is a non-rigid shape. In the same way that a square can be flexed into a rhombus and reduce the area by making the rhombus thinner, an octagon can be flexed into a shape with as small an area as you like.Its maximum area is 482.8 cm2(approx).An octagon is a non-rigid shape. In the same way that a square can be flexed into a rhombus and reduce the area by making the rhombus thinner, an octagon can be flexed into a shape with as small an area as you like.Its maximum area is 482.8 cm2(approx).
The area of a rhombus is half the product of the diagonals. A = 1/2bc. The diagonals (of length b and c) intersect at right angles and form two congruent triangles either side of one chosen diagonal. The area of one such triangle is 1/2b x 1/2c (area of a triangle = 1/2 base x height). The area of both triangles and therefore the area of the rhombus is 2(1/2b x 1/2c) = 1/2bc.
The answer is given below.
ind the area of the rhombus if AE = 20 m and DE = 32 m.
Find the area of a rhombs with diagonals that measure 8 and 10.
if those are the measurements then that is not a rhombus, rhombi are 4 sided shapesthat have all equal sides
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Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
That is one of the ways of finding the area of a rhombus. The area is half the product of the diagonals. In this case, 1/2 of 7 x 4.4 or .154. You can also find the area of a rhombus by using one side as the base and finding an altitude for that base and multiplying them. There is a third way using trigonometry.
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm? . Area = base * height Altitude = height. Altitude = 4 cm . A rhombus has all 4 sides equal, so the base = 6 cm . Area = base * height . Area = ____sq. cm.
130 is the area.
If side is given too, then you can find area with one diagonal. As diagonals bisect each other in a rhombus at 90°, Using Pythogoras Theorem: (Half d1)² = (side)² - (Half d2)²