The formula is: y = mx+b whereas m is the slope and b is the y intercept
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
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If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
there is only one way i know how to find the slope of a hyperbola and that is taking the implicit derivative of its equation, and solving for dy/dx but the answer is Slope= (x)*(b^2) / (y)*(a^2)
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
We know that its slope is negative, but without an equation or some points the line passes through we can't determine the actual value of the slope.
i dont know 8x+5y=89
There are a couple ways to determine the equation of a line without graphing. How to proceed depends on what you know about the line. Do you know a point, (x1, y1), and slope, m? Then use the point-slope formula, Do you know two points on the line, say (x1, y1) and (x2, y2)? Then use the two-point formula,
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
Slope Intercept form is meant for a line, so if you know the slope m in the equation y=mx+b then with a given point say (3,4) and say the slope of the line was 2 then the equation would read y=2x+4.
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The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.
If the algebraic equation is linear, in the form y = mx + b, the slope is simply m; the difference in y of any 2 points divided by the difference in x of those points (rise over run). If the equation is non-linear, the slope is the first derivative of that equation, from calculus. You woul need to know calculus to solve in this case. The slope will vary from point to point, unlike the linear case, where slope is constant.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
First, you have to have domain and range, a graph, or an equation in slope-intercept form ( y=mx + b) to determine if an equation is a function. The slope intercept form here is Y=3/1x + 1. So Yes, this equation is a function. If you want to know how to convert into y=mx + b form, ask how to do it here, or look it up on the internet. Hope I helped :-)
First you subtract X from both sides. The equation then becomes Y = 7 - X. You can rewrite this as Y = -X + 7. Then the equation is in slope-intercept form Y = mx + b where m is the slope. By using this definition you can know that the coefficient attached to X is the slope. In the equation, X has a coefficient of -1 so the slope is -1.
You know when the slope of a line is negative when m in the slope-intercept form equation y=mx+b is negative. For example, y=-3x+2 has a negative slope since m (which is -3 in this case) is negative. This is the same when finding a positive slope, because if m is positive, then the slope is positive.