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You have : y = e^(5x)^2 and de^u/dx = [ e^u ] [ du/dx ]

dy/dx = [ e^(5x)^2 ] [ 10x ] <--------------------------------------

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If y = e25x then dy/dx = 5e2.

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Q: How do you find dy by dx of y equals e square 5x?
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If y equals the integral from 5x on top to cosx on bottom of cos of u squared du what is y'?

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What is the derivative of the square root x?

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