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There are infinitely many polynomials of order 4 that will give these as the first four numbers and any one of these could be "the" explicit formula.

There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.

For example,

t(n) = (-17*n^4 + 170*n^3 - 575*n^2 + 830*n - 400)/4 for n = 1, 2, 3, ...

The Simplest, though is

t(n) = 5*n^2 - 5*n + 2 for n = 1, 2, 3, ...

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What type of graph represents the sequence given by the explicit formula an 5 n - 12?

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The explicit formula for an arithmetic sequence is given by an = a1 + (n-1)d, where a1 is the first term and d is the common difference. In this case, the first term a1 is 16, and the common difference d is 4. Therefore, the explicit formula for the arithmetic sequence is an = 16 + 4(n-1) = 4n + 12.


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To find the 400th term of the sequence, we first identify the first term ( a_1 = 8 ) and the common difference ( d = 20 - 8 = 12 ). Using the explicit formula ( a_n = a_1 + (n - 1) \cdot d ), we can substitute ( n = 400 ): [ a_{400} = 8 + (400 - 1) \cdot 12 = 8 + 399 \cdot 12 = 8 + 4788 = 4796. ] Thus, the 400th term is 4796.


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Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!


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To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.


What is the nth term of the sequence 18 12 6 0 -6?

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What is the nth term for 12 10 8 6 4?

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