There are infinitely many polynomials of order 4 that will give these as the first four numbers and any one of these could be "the" explicit formula.
There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
For example,
t(n) = (-17*n^4 + 170*n^3 - 575*n^2 + 830*n - 400)/4 for n = 1, 2, 3, ...
The Simplest, though is
t(n) = 5*n^2 - 5*n + 2 for n = 1, 2, 3, ...
> since the value rises by nine at each step and the first term is 12 the formula for > the nth term is: 12+(n-1)*9 Which simplifies to Sn = 9n + 3
10-2x for x = 0, 1, 2, 3, ... Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.
There can be no answer because a number sequence, in itself, is not a question.
It is 60.
*12, /4, *12, /4
-7
-7
12, 6, 0, -6, ...
The nth term of the sequence is expressed by the formula 8n - 4.
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
n=1 a(1) = 0.001 n=2 a(2) = 0.012 n=3 a(3) = 0.144 n=4 a(4) = 1.728 n=5 a(5) = 20.736 .... n=k a(k) = (12^(k-1))/1000 let n = k+1 a(k+1) = 12^(k)/1000 12(ak) = a(k+1) 12(12^k-1)/1000 = 12^k/1000 the 12 gets absorbed here. 12^(k-1+1)/1000 = 12^k/1000 Valid for k and k+1 therefore our equation A(n) = 12^(n-1)/1000, n(greater than or equal to) 1
t(n) = 12*n + 5
> since the value rises by nine at each step and the first term is 12 the formula for > the nth term is: 12+(n-1)*9 Which simplifies to Sn = 9n + 3
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
i need it nowww
The formula is: (12-2)*180 = 1800 degrees
A geometric sequence is a sequence where each term is a constant multiple of the preceding term. This constant multiplying factor is called the common ratio and may have any real value. If the common ratio is greater than 0 but less than 1 then this produces a descending geometric sequence. EXAMPLE : Consider the sequence : 12, 6, 3, 1.5, 0.75, 0.375,...... Each term is half the preceding term. The common ratio is therefore ½ The sequence can be written 12, 12(½), 12(½)2, 12(½)3, 12(½)4, 12(½)5,.....