There are infinitely many polynomials of order 4 that will give these as the first four numbers and any one of these could be "the" explicit formula.
There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
For example,
t(n) = (-17*n^4 + 170*n^3 - 575*n^2 + 830*n - 400)/4 for n = 1, 2, 3, ...
The Simplest, though is
t(n) = 5*n^2 - 5*n + 2 for n = 1, 2, 3, ...
> since the value rises by nine at each step and the first term is 12 the formula for > the nth term is: 12+(n-1)*9 Which simplifies to Sn = 9n + 3
10-2x for x = 0, 1, 2, 3, ... Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.
To find the nth term of a sequence, we first need to determine the pattern or rule that governs the sequence. In this case, the sequence appears to be increasing by adding consecutive odd numbers: 3, 6, 9, 12, and so on. Therefore, the nth term formula for this sequence is Tn = 3n^2 + n. So, the nth term for the sequence 4, 7, 13, 22, 34 is Tn = 3n^2 + n.
There can be no answer because a number sequence, in itself, is not a question.
It is 60.
-7
-7
The explicit formula for an arithmetic sequence is given by an = a1 + (n-1)d, where a1 is the first term and d is the common difference. In this case, the first term a1 is 16, and the common difference d is 4. Therefore, the explicit formula for the arithmetic sequence is an = 16 + 4(n-1) = 4n + 12.
To find the 400th term of the sequence, we first identify the first term ( a_1 = 8 ) and the common difference ( d = 20 - 8 = 12 ). Using the explicit formula ( a_n = a_1 + (n - 1) \cdot d ), we can substitute ( n = 400 ): [ a_{400} = 8 + (400 - 1) \cdot 12 = 8 + 399 \cdot 12 = 8 + 4788 = 4796. ] Thus, the 400th term is 4796.
t(n) = 12*n + 5
12, 6, 0, -6, ...
Well, honey, looks like we've got ourselves an arithmetic sequence here with a common difference of 7. So, to find the nth term, we use the formula a_n = a_1 + (n-1)d. Plug in the values a_1 = 12, d = 7, and n to get the nth term. Math doesn't have to be a drag, darling!
To find the nth term of a sequence, we first need to identify the pattern or rule governing the sequence. In this case, the sequence appears to be increasing by 4, then 8, then 12, then 16, and so on. This pattern suggests that the nth term can be represented by the formula n^2 + n, where n is the position of the term in the sequence. So, the nth term for the given sequence is n^2 + n.
To find the nth term of a sequence, we first need to identify the pattern or rule that governs the sequence. In this case, the sequence is decreasing by 6 each time. Therefore, the nth term can be represented by the formula: 18 - 6(n-1), where n is the position of the term in the sequence.
The nth term of the sequence is expressed by the formula 8n - 4.
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
The given sequence is decreasing by 2 each time, starting from 12. To find the nth term, we can use the formula for an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, (a_1 = 12), (d = -2), and we need to find the general formula for the nth term. Therefore, the nth term for the sequence 12 10 8 6 4 is (a_n = 12 + (n-1)(-2)), which simplifies to (a_n = 14 - 2n).