Two adjacent sides of a square and the diagonal joining their ends froms a right angle triangle. The legs of the triangle are 10 ft each and the diagonal is the hypotenuse. By pythagoras, diagonal = sqrt(102 + 102) = 10*sqrt(2) = 14.142 ft (to 3 dp).
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10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet
If diagonal is 10 then each side is sqrt 50 (Pythagoras) and area is sqrt 50 x sqrt 50 ie 50
10 cm
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
The formula for what? Its perimeter, area, diagonal, etc.