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Two adjacent sides of a square and the diagonal joining their ends froms a right angle triangle. The legs of the triangle are 10 ft each and the diagonal is the hypotenuse. By pythagoras, diagonal = sqrt(102 + 102) = 10*sqrt(2) = 14.142 ft (to 3 dp).

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Q: How do your find the diagonal measurement for a 10 ft square?
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What is the diagonal measurement for a square 10' x 16'?

10' x 16' is not a square but a rectangle and the diagonal is square root of (10^2 + 16^2) = square root of (100 + 256) = square root of 356 which is 18.867 feet


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Using Pythagoras' theorem it is: 10 times the square root of 2 which is about 14.142 to 3 decimal places.


What is the length of the diagonal of a 10 by 10 ft square?

To find the length of the diagonal of a square, we can use the Pythagorean theorem. In a square, the diagonal divides the square into two right-angled triangles. The Pythagorean theorem states that the square of the length of the diagonal is equal to the sum of the squares of the two sides. Therefore, for a 10 by 10 ft square, the length of the diagonal would be the square root of (10^2 + 10^2) which is √(100 + 100) = √200 = 10√2 feet.


What is the diagonal of a square with a side of 10?

14 The ratio of the side of a square to the diagonal is 1.4.


How do you find area of square if diagonal is given?

Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2


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