To find the length of the diagonal of a square, we can use the Pythagorean theorem. In a square, the diagonal divides the square into two right-angled triangles. The Pythagorean theorem states that the square of the length of the diagonal is equal to the sum of the squares of the two sides. Therefore, for a 10 by 10 ft square, the length of the diagonal would be the square root of (10^2 + 10^2) which is √(100 + 100) = √200 = 10√2 feet.
12.73 feet
18.9 feet
The diagonal of an 8 ft by 10 ft square, by Pythagoras, would be sqrt(82 + 102) = sqrt(64+100) = sqrt(164) = 12.806 ft (to 5 sig figs)
The edge length of a cube with a diagonal of 9 ft is: 5.196 feet.
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, the diagonal measurement would be the square root of (7^2 + 8^2) = √(49 + 64) = √113. Therefore, the diagonal measurement of a 7 ft by 8 ft square is approximately 10.63 feet.
The length of the diagonal is 208.7*sqrt(2) = 295.1 ft.
10 ft Because 102+102 = 200 and the square root of this is 10 times the square root of 2 which complies with Pythagoras' theorem.
The diagonal length of a square with a 900 square foot area is: 42.43 feet.
18.9 feet
3.5 ft
12.73 feet
18.9 feet
Approximately 17 feet.
Since a square has right angles, you can use the Pythagorean Theorem to calculate the diagonal. Specifically, the diagonal of a square is equal to the length of a side, multiplied by the square root of 2.
Two adjacent sides of a square and the diagonal joining their ends froms a right angle triangle. The legs of the triangle are 10 ft each and the diagonal is the hypotenuse. By pythagoras, diagonal = sqrt(102 + 102) = 10*sqrt(2) = 14.142 ft (to 3 dp).
5.7 ft
The diagonal of an 8 ft by 10 ft square, by Pythagoras, would be sqrt(82 + 102) = sqrt(64+100) = sqrt(164) = 12.806 ft (to 5 sig figs)