16 1-inch cubes
To find the total surface area of the 3-cube tower, we need to calculate the surface area of each cube individually and then add them together. The surface area of a cube is given by 6 times the side length squared. For the 3-inch cube: 6 * 3^2 = 54 square inches For the 2-inch cube: 6 * 2^2 = 24 square inches For the 1-inch cube: 6 * 1^2 = 6 square inches Adding these together: 54 + 24 + 6 = 84 square inches Therefore, the total surface area of the 3-cube tower is 84 square inches.
True
5x5x6=150 If the cube has 5 inch long sides then each side has an area of 5 inches x 5 inches which equals 25 sqare inches. The cube has 6 sides so the total area of paper needed to cover it is 25 square inches x 6, which is 150 square inches of paper.
The volume of a cube is the length of the side cubed, orV = s3V = 93V = 729 in3It is: 9*9*9 = 729 cubic inches
Eight 4 inch cubes are needed to build and 8 inch cube.
Eight half inch cubes would fill a one inch cube.
A 41 inch cube is 41X41X41 inches. 413=68921 cubic inches. A 41 inch cube can be cut into 68921 one-inch cubes.
16 1-inch cubes
4
8
8
27 of them.
4 of them can.
No. A cube with sides which are 1 centimetre long or that of 1 inch are both unit cubes, as is a cube with sides of 1 decimetre (volume = 1 litre).
125 of them.
I make it as 64. 4 X 4 X 4= 64