If you allow for zeros, that's 10^16, which is ten quintillion, or 10,000,000,000,000,000.
If not, it's 9^16, which is 1,853,020,188,851,841, or 1.85 quintillion. (1.85x10^15)
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To calculate the number of 4-digit combinations you can get from the numbers 1, 2, 2, and 6, we need to consider that the number 2 is repeated. Therefore, the total number of combinations is calculated using the formula for permutations of a multiset, which is 4! / (2!1!1!) = 12. So, there are 12 unique 4-digit combinations that can be formed from the numbers 1, 2, 2, and 6.
There are 27 of them.
There are 167960 9 digits combinations between numbers 1 and 20.
90
Any 3 out of 4 = 4. Each set can be arranged 6 ways so 24 different numbers.