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Assuming that the first digit can't be zero:

If repetition of digits is permitted: (5 x 6 x 6) = 180 numbers of 3 digits.

If repetition of digits is not permitted: (5 x 5 x 4) = 100 numbers of 3 digits.

Q: How many 3 digit numbers are possible from the digits 012345?

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012345 or -543210, if negative numbers are permitted.

543210

That makes:* 8 options for the first digit * 8 options for second digit * 10 options for the third digit * ... etc. Just multiply all the numbers together.

Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.

The number 1234567890 can create about 39 of 40 4 digit numbers.

Related questions

012345 or -543210, if negative numbers are permitted.

543210

543,210. If you can use them all multiple times, then it is 555,555.

There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.

There are 9 possible numbers for the first digit (one of {1, 2, ..., 9}); with 9 possible digits for the second digit (one of {0, 1, 2, ..., 9} which is not the first digit)); with 8 possible digits for the third digit (one of {0, 1, 2, ..., 9} less the 2 digits already chosen); This there are 9 × 9 × 8 = 648 such numbers.

It is possible to create a 3-digit number, without repeated digits so the probability is 1.

It can have 4 digits, because the highest possible two digit numbers 99*99=9801.

There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.

There are 2941 4-digit numbers such no two of its digits differ by 1.

There are 30,240 different 5-digit numbers. Math: 10*9*8*7*6 1st digit has 10 possible choices (0-9) 2nd digit has 9 possible choices (one of the digits was used in the 1st digit) 3rd digit has 8 possible choices 4th digit has 7 possible choices 5th digit has 6 possible choices

-4

There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.