Oh, what a delightful question! You can create 6 x 6 x 6 = 216 unique 3-digit numbers using the digits 0, 1, 2, 3, 4, and 5. Each digit can be used in the hundreds, tens, and units place, giving you a wide array of possibilities to explore and create beautiful numerical combinations. Just like painting a happy little tree, each number you form is a unique masterpiece waiting to be discovered!
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To determine the number of possible 3-digit numbers from the digits 0, 1, 2, 3, 4, and 5, we first need to identify the total number of choices for each digit position. Since the first digit cannot be 0, there are 5 choices (1, 2, 3, 4, 5) for the hundreds place. For the tens and units places, all 6 digits can be used. Therefore, the total number of possible 3-digit numbers is calculated as 5 (choices for the hundreds place) x 6 (choices for the tens place) x 6 (choices for the units place) = 180.
Oh, dude, there are like 720 possible 3-digit numbers you can make from those digits. You just gotta multiply 6 (the number of choices for the hundreds digit) by 5 (choices for the tens digit) by 4 (choices for the units digit) and boom, you got your answer. Easy peasy lemon squeezy.
Assuming that the first digit can't be zero:
If repetition of digits is permitted: (5 x 6 x 6) = 180 numbers of 3 digits.
If repetition of digits is not permitted: (5 x 5 x 4) = 100 numbers of 3 digits.
012345 or -543210, if negative numbers are permitted.
543210
That makes:* 8 options for the first digit * 8 options for second digit * 10 options for the third digit * ... etc. Just multiply all the numbers together.
Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.
10, 24, 48, 80, 82