Oh, what a delightful question! You can create 6 x 6 x 6 = 216 unique 3-digit numbers using the digits 0, 1, 2, 3, 4, and 5. Each digit can be used in the hundreds, tens, and units place, giving you a wide array of possibilities to explore and create beautiful numerical combinations. Just like painting a happy little tree, each number you form is a unique masterpiece waiting to be discovered!
012345 or -543210, if negative numbers are permitted.
543210
That makes:* 8 options for the first digit * 8 options for second digit * 10 options for the third digit * ... etc. Just multiply all the numbers together.
Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.
10, 24, 48, 80, 82
012345 or -543210, if negative numbers are permitted.
543210
To find the even two-digit numbers where the sum of the digits is 5, we need to consider the possible combinations of digits. The digits that sum up to 5 are (1,4) and (2,3). For the numbers to be even, the units digit must be 4, so the possible numbers are 14 and 34. Therefore, there are 2 even two-digit numbers where the sum of the digits is 5.
543,210. If you can use them all multiple times, then it is 555,555.
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
There are 9 possible numbers for the first digit (one of {1, 2, ..., 9}); with 9 possible digits for the second digit (one of {0, 1, 2, ..., 9} which is not the first digit)); with 8 possible digits for the third digit (one of {0, 1, 2, ..., 9} less the 2 digits already chosen); This there are 9 × 9 × 8 = 648 such numbers.
It can have 4 digits, because the highest possible two digit numbers 99*99=9801.
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
There are 2941 4-digit numbers such no two of its digits differ by 1.
There are 30,240 different 5-digit numbers. Math: 10*9*8*7*6 1st digit has 10 possible choices (0-9) 2nd digit has 9 possible choices (one of the digits was used in the 1st digit) 3rd digit has 8 possible choices 4th digit has 7 possible choices 5th digit has 6 possible choices
-4