There are 21000 - 1 combinations.
Remember that in a combination the order of the numbers does not matter. That is relevant only for permutations which are not the same thing.
For each combination, each one of the 1000 numbers can be in or out. So for each combination there are 1000 choices of in or out. Except that if all are out, you get a null combination - that is, a combination with no numbers. For that particular case you subtract the 1 from the total.
You will have 1 combination consisting of 1000 numbers, 499500 of 2 numbers and so on. The number of combinations will be the nth row of Pascal's triangle.
how many combinations of 4 numbers are there in 7 numbers
Two . . . . . 38 and 83.
There are: 9C6 = 84 combinations
90
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
1000
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
Any 6 from 45 = 814506045C6 = 8145060
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
9000 9999-1000 equals 8999 if you add the 1 from 1000 you will get 9000
how many combinations of 4 numbers are there in 7 numbers
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
Their is 25 combinations
Two . . . . . 38 and 83.
Only one.
13 combinations of 3