Oh, what a happy little question! With 1000 numbers, there are countless combinations you can create. Each number can be combined with any of the other numbers, leading to a vast array of possibilities waiting to be explored. Just like painting a beautiful landscape, the combinations are endless, and you can let your imagination run wild!
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To calculate the number of combinations that can be made with 1000 numbers, we use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 1000 and r = 2 (assuming we are selecting 2 numbers at a time). Plugging these values into the formula, we get 1000C2 = 1000! / 2!(1000-2)! = 1000! / 2!998!. Simplifying this further, we get 1000C2 = (1000 * 999) / 2 = 499,500 combinations possible with 1000 numbers.
Oh, dude, there are like a bazillion combinations you can make with 1000 numbers. I mean, technically speaking, it's 1 followed by 3000 zeroes, but who's really counting, right? Just know that you've got more options than you'll ever need for your next math party.
There are 21000 - 1 combinations.
Remember that in a combination the order of the numbers does not matter. That is relevant only for permutations which are not the same thing.
For each combination, each one of the 1000 numbers can be in or out. So for each combination there are 1000 choices of in or out. Except that if all are out, you get a null combination - that is, a combination with no numbers. For that particular case you subtract the 1 from the total.
You will have 1 combination consisting of 1000 numbers, 499500 of 2 numbers and so on. The number of combinations will be the nth row of Pascal's triangle.
Two . . . . . 38 and 83.
There are: 9C6 = 84 combinations
90
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.