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what is the anwer for x=3 and x=2
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∙ 14y ago
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What is x5 divided by x3?
1.6667
Factor x3 plus 8?
x3 + 8 = x3 + 23 = (x + 2)[x2 - (x)(2) + 22] = (x + 2) (x2 - 2x + 4)
Factor x5 plus x2?
x2(x3 + 1) is the best you can do there.
How do you factor x3 plus 1?
x3 + 1 = x3 + x2 - x2 - x + x + 1 = x2(x + 1) - x(x + 1) +1(x + 1) = (x + 1)(x2 - x + 1)
What is x3-x2-2x plus 2 factored?
x3 - x2 - 2x +2 you can divide this into two parts for now x3 - x2 and -2x +2 factor out everything you can from both x2(x-1) and -2(x+1) since the insides of the parentheses are the same, we can put them together, then multiply it by the sum of the two parts outside the parentheses. (x-1)(x2-2)
What is x2 times x3?
If x2 and x3 are meant to represent x2 and x3, then x2 times x3 = x5 You find the product of exponent variables by adding the exponents.
What is x3-x2-x minus 2 factored?
x3-x2
How do you factor x3?
X3 X(X2) X2(X) and, X * X * X
Factor by grouping 3-3x plus x2-x3?
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
How do you factor x3 plus x2-3x-3?
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
What is x3-x2 plus 2x factored?
x3 - x2 + 2x = x*(x2 - x + 2) which cannot be factored further.
How do you compute quadratic equation using java?
What do you mean by "compute"? Do you want to graph it? Factor it? Calculate it's function given a set of points that lie on it? If you're looking to compute the function given three points that fall on the parabola, then I have just the code for you. If you're given three points, (x1, y1), (x2, y2) and (x3, y3), then you can compute the coefficients of your quadratic equation like this: a = (y1 * (x2 - x3) + y2 * (x3 - x1) + y3 * (x1 - x2)) / (x1 * x1 * (x2 - x3) + x2 * x2 * (x3 - x1) + x3 * x3 * (x1 - x2)) b = (y1 - y2) / (x1 - x2) - a * (x1 + x2); c = y1 - (x1 * x1) * a - x1 * b; You now can calculate the y co-ordinate of any point given it's x co-ordinate by saying: y = a * x * x + b * x + c;
What is x3 - x2 plus x - 2 factored?
x3 - x2 + x - 2 has no rational factors.
What is a grouping factor for polynomial x3 ax 3a 3x2?
x3 + ax + 3a + 3x2 = x (x2 + a) + 3 (a + x2) = x (x2 + a) + 3 (x2 + a) = (x2 + a)(x + 3) Checking the work: x3 + ax + 3x2 + 3a or x3 + 3x2 + 3a + ax = x2 (x + 3) + a (3 + x) = x2 (x + 3) + a (x + 3) = (x + 3)(x2 + a)
How do you factor x3-x2?
Answer: x (x2-x)
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
