It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
6x - 3y = 12y intercept at x = 0 is y = 4x intercept at y = 0 is x = 2the graph is straight line passing through the two points: (0, 4) and (2, 0)
Restate the question: How do you graph 7x+2y=14? The easiest way to graph this equation is to find the intercepts. . . To find the y-intercept, let x=0: 7(0)+2y=14 <=> 2y=14 <=> 2y/2=14/2 <=> y=7, so mark the point (0,7) on the graph. To find the x-intercept, let y=0: 7x+2(0)=14 <=> 7x=14 <=> x=2, so mark (2,0) on the graph and draw a straight line through the 2 points. With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!
If D > 0 then the graph intersects the x-axis 2 times.If D = 0 then the the x-axis is tangent to the graph.If D < 0 then the graph doe not intersects the x-axis.
Two ways. You can solve for y and then use slope intercept or use x and y intercepts. If x=0 then y=5 (0,5) If y=0 then x=-6 (-6,0) Graph those two points and then draw a line through them.
No.A directly proportional graph has an equation of the form y = mx. It always passes through the origin.A linear graph will have an equation in the from y = mx + c. This has a y-intercept at (0, c). It doesn't pass through the origin unless c = 0. The directly proportional graph is a special case of a linear graph.
For a direct variation, y=kx where k is the constant of variation if x =0 then y=0 and the graph of y=kx passes through the origin. -Indiana Prentice Hall Algebra 2 Text Book.
Graphs of direct variation pass through the origin so the y-intercept would be 0.
Some do and some don't. It's possible but not necessary.
It intercepts the y axis at (0, 5) and it intercepts the x axis at (-2.3, 0) passing through the I, II and III quadrants
The graph of ax + by = c is a straight line going through the points (0, c/b) and (c/a, 0).
The graph of y = log(x) is defined only for x>0. The graph is a monotonic increasing function over its domain. It starts from an asymptotic "minus infinity" when x approaches 0. It passes through the value y = 0 when x = 1. The graph is illustrated at the link below.
It's hard to say, since we're having such a difficult time seeing the graph.
It is the point of origin of the x and y axes of the graph
Greenwich England
A straight line through the points (0, 1) and (-0.4, 0).
6x - 3y = 12y intercept at x = 0 is y = 4x intercept at y = 0 is x = 2the graph is straight line passing through the two points: (0, 4) and (2, 0)