No, it is not.
Since that's a fairly small set, you should be able to check all combinations (for 2 numbers, there are only 4 possible multiplications), and see whether the result is in the set.
Yes. The set of real numbers is closed under addition, subtraction, multiplication. The set of real numbers without zero is closed under division.
You don't say that "an integer is closed". It is the SET of integers which is closed UNDER A SPECIFIC OPERATION. For example, the SET of integers is closed under the operations of addition and multiplication. That means that an addition of two members of the set (two integers in this case) will again give you a member of the set (an integer in this case).
division
A set is closed under a particular operation (like division, addition, subtraction, etc) if whenever two elements of the set are combined by the operation, the answer is always an element of the original set. Examples: I) The positive integers are closed under addition, because adding any two positive integers gives another positive integer. II) The integers are notclosed under division, because it is not true that an integer divided by an integer is an integer (as in the case of 1 divided by 5, for example). In this case, the answer depends on the definition of "whole numbers". If this term is taken to mean positive whole numbers (1, 2, 3, ...), then the answer is no, they are not closed under subtraction, because it is possible to subtract two positive whole numbers and get an answer that is not a positive whole number (as in the case of 1 - 10 = -9, which is not a positive whole number)
No.
aye
Assuming its endpoints are not equal, a closed interval of the real number line a has an infinite number of real numbers in it. Closed intervals of other ordered sets can have either a finite or an infinite number of elements. I am not sure I answered your question because I am not exactly sure what you are asking. Could you be more specific? Are you talking about a closed interval of the real number line or closed interval of some other ordered set? By finite do you mean 'containing a finite number of elements' or do you mean 'bounded by a finite number'.
Open interval does not include its end points while closed interval includes
There is more than one notation, but the open interval between a and b is often written (a,b) and the closed interval is written [a,b] where a and b are real numbers. Intervals may be half open or half closed as well such as [a,b) or (a,b]. For all real numbers, it is (-infinity,+infinity), bit use the infinity symbol instead (an 8 on its side).
An interval on the number scale is a set of numbers between two end-point. Thus the closed interval [a, b] comprises all number between a and b as well as the two end points. An interval is open if neither end point is included, and semi-open (or semi-closed) if one end in included and the other is not.
Yes, if it is the closed interval. No, if it is the open interval.
Probability of an even must lie in the closed interval [0, 1].Probability of an even must lie in the closed interval [0, 1].Probability of an even must lie in the closed interval [0, 1].Probability of an even must lie in the closed interval [0, 1].
A closed interval.
In an interval it means that the 2 is included.
Because infinity is not a number.
Usually as a range in brackets. The curved brackets, ( and ), are used for "open" intervals, where the end points are not included. The square brackets, [ and ], are used for closed intervals where the end points are included. You can also have semi-closed brackets. For example x is in (3,5) is equivalent to 3 < x < 5 x is in [3,5] is equivalent to 3 ≤ x ≤ 5 x is in (3,5] is equivalent to 3 < x ≤ 5