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"Sin" stands for "sinus". The sinus of any angle is defined, in a rectangle triangle, as the ratio of the side opposed to the angle and the hypotenuse. The sinus is useful because it is unique to any angle, which means that the ratio of the opposite side and the hypotenuse in any rectangle triangle is always the same given a certain angle. "Cos" stands for "cosinus". The cosinus of any angle is defined, in a rectangle triangle, as the ratio of the side adjacent to the angle and the hypotenuse. Like the sinus of an angle, the cosinus of an angle will always be constant, which means that, given a certain angle, the ratio will always be the same even if the triangles don't have the same size. Sinus and Cosinus are very useful to determine missing informations in rectangle triangles. In fact, with only two informations (angle and side), you can find every information on this triangle.
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Blakethe suitable identity to get the each of the following product [2a- 7] [ 2a -7]
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How do you show that 2 sin squared x minus 1 divided by sin x minus cos x equals sin x plus cos x?
(2 sin^2 x - 1)/(sin x - cos x) = sin x + cos x (sin^2 x + sin^2 x - 1)/(sin x - cos x) =? sin x + cos x [sin^2 x - (1 - sin^2 x)]/(sin x - cos x) =? sin x + cos x (sin^2 x - cos^2 x)/(sin x - cos x) =? sin x + cos x [(sin x - cos x)(sin x + cos x)]/(sin x - cos x) =? sin x + cos x sin x + cos x = sin x + cos x
How do you simplify tan theta cos theta?
Remember that tan = sin/cos. So your expression is sin/cos times cos. That's sin(theta).
Why does the derivative of sin x equal - cos x?
It isn't. The derivate of sin x = cos x.It isn't. The derivate of sin x = cos x.It isn't. The derivate of sin x = cos x.It isn't. The derivate of sin x = cos x.
How do you factor sin squared times x plus cos2x -cosx equals 0?
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Use trigonometric identities to write each expression in terms of a single trigonometric function or a constant. simplify cos t sin t?
Thanks to the pre-existing addition and subtraction theorums, we can establish the identity:sin(a+b) = sin(a)cos(b)+sin(a)cos(b)Then, solving this, we getsin(a+b) = 2(sin(a)cos(b))sin(a)cos(b) = sin(a+b)/2a=b, sosin(a)cos(a) = sin(a+a)/2sin(a)cos(a) = sin(2a)/2Therefore, the answer is sin(2a)/2.
