The product of two consecutive integers is 210?

Answer 1

Let the integers by n & n+1

Their product is

n(n+1) = 210

n^2 + n = 210

n^2 + n - 210 = 0

Factor

( n - 14)(n + 15) = 0

n = 14 & n = -15

The consecutive integers being 14 & 15.

Answer 2

You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers.

2) Call the two consecutive integers "n" and "n+1", and solve the equation:

n(n+1)=210

Answer 3

Let's denote the two consecutive integers as ( n ) and ( n+1 ). The product of these two integers can be expressed as ( n(n+1) = 210 ). Simplifying, we get the quadratic equation ( n^2 + n - 210 = 0 ). Solving this equation using the quadratic formula, we find that the two integers are 14 and 15.

Answer 4

Yes, it is possible.