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What are the three consecutive odd integers such that the sum of the first twice the second and three times the third is 82?
Wiki User
∙ 14y ago
Numbers are x, x + 2 and x + 4. then x + 2(x + 2) + 3(x + 4) = 82 ie x + 2x + 4 + 3x + 12 = 82 ie 6x = 82 - 4 - 12 = 66 therefore x =11 and the other numbers are 13 and 15. Check: 11 + (2 x 13) + (3 x 15) = 11 + 26 + 45 = 82 QED
Wiki User
∙ 14y ago
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How do you find consecutive integers?
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
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If the sum of the first two of the five consecutive odd integers is 52what is the sum of the last two integers?
Let the first odd integer be x, then the second one is x + 2. So we have: x + (x + 2) = 52 2x + 2 = 52 subtract 2 to both sides 2x = 50 divide by 2 to both sides x = 25 Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33. So the sum of the last two integers is 64 ( 31 + 33).
Cindy had three consecutive even integers She found that the product of their sum and 3 was 20 greater than 8 times the third integerWhat were Cindys integers?
greater
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The three integers, since they are consecutive, can be listed as a, a+1, and a+2. Twice the first is 2a. Three times the third is 3(a+2) = 3a+6. First make a formula of the information given: 2a+(3a+6)= -24 Next, solve the formula: 5a + 6 = -24 Subtract 6 from each side. 5a = -30 Divide each side by 5. a = -6 The three consecutive numbers are -6, -5, and -4.
What are the 2 consecutive integers such that the sum of one-third the first and one-fourth the second is 9?
-7
What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?
10-11-12
Find three consecutive even integers such that the sum of the first twice the second and three times the third is 124?
18, 20 and 22
FIND Three consecutive integers such that the sum of the second and the third is 17 Which equation would be used to solve this word problem?
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.
What is the sum of three consecutive integers if the sum of the first and third numbers is 33 less than 3 times the second number?
Their sum is 99.
How do you find consecutive integers?
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
What are three consecutive integers such that the sum of five times the first six times the second and seven times the third is 148?
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
What is the sum of 3 consecutive integers if the sum of the first and third number is two times the second number?
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Find four consecutive integers such that the sum of the second and fourth is 132 show the work?
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
Find 3 consecutive even integers if the product of the first integer and two two less than the second integer is four more than five times the third integer and what is the let statement?
The let statement is: let the smallest of the three integers be x.
Find three consecutive integers such that the sum of the first twice the second and three times the third is 86?
n + 2(n+1) + 3(n+2) = 86 n + 2n + 2 + 3n + 6 = 86 6n = 86 - 2 - 6 6n = 78 n = 13 Three consecutive integers are = 13,14,15
Find 3 consecutive whole numbers such that the first and third add up to 118?
121
