The median is the middle value of a list of numbers. In [1,6,34] the median value is 6.
You find the median to find the middle number
6 is the median of 10 numbers
Median is: (54+72)/2 = 63.
the median is the middle number in a set of data.
The median is the midpoint of the data set. So half the observations are greater than the median and half are smaller.
The median, by definition, tells you the "half way point" of your data. Exactly half of the observations in the dataset will be less than the median and half will be greater than the median.
the midpoint of the data set
Tell me
There is no direct relationship between the range and the median. So knowing that your median is 20 does not automatically give you the range. The median is just the middle value. That does not tell you what the first and last values are, which is what you need to know to find the range. The median of 19, 20 and 21 is 20, and the range is 2. The median of 4, 20 and 79 is also 20, but the range is 75. The median of 8, 16, 17, 23, 50 and 320 is also 20, but the range is 312. So, as you can see, the Median in no way can tell you what the range will be. You need to know what all of the numbers are, or at least the lowest and highest to know the range.
It's impossible to tell given the data. The median is the value dividing the half of the elements above the value and the half below it.
Well, there is no telling if the mean and median are the same. It can be, but most of the time it's not. You can't tell, but I am only in 5th grade, so I might be wrong.
I think it means that our data includes outliers.
The median is 5.The median is 5.The median is 5.The median is 5.
It is not possible to tell without more information. As it is, it could be any of them.
The median is 28.The median is 28.The median is 28.The median is 28.
If the median is exactly in the middle of the box, and the box is exactly in the middle of the whiskers, then skewness = 0. The data are skewed if either the median is off-centre in the box, or if the box is off-centre overall.