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What formula name that gives the solutions for x in a quadratic equation?
Wiki User
∙ 11y ago
This formula is called the quadratic formula.
Wiki User
∙ 11y ago
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What does it mean in algebra to complete the square?
A quadratic equation can be solved by completing the square which gives more information about the properties of the parabola than with the quadratic equation formula.
Is there a solution to the quadratic equation of 3x squared -10x equals -5?
Yes because rearranging it into the form of 3x2-10x+5 = 0 makes the discriminant of the quadratic equation greater than zero which means it will have two different solutions. Solving the equation by means of the quadratic formula gives x as being 2.721 or 0.613 both corrected to 3 decimal places.
How many sides does an irregular polygon have if it has 252 diagonals showing work?
Let its sides be x and rearrange the diagonal formula into a quadratic equation:- So: 0.5(x^2-3x) = 252 Then: x^2-3n-504 = 0 Solving the quadratic equation: gives x a positive value of 24 Therefore the polygon has 24 sides irrespective of it being irregular or regular
What are two algebraic methods for solving quadratic equations?
Finally, there are two methods to use, depending on if the given quadratic equation can be factored or not. 1.- The first one is the new Diagonal Sum Method, recently presented in book titled: "New methods for solving quadratic equations" (Trafford 2009). This method directly gives the two roots in the form of two fractions, without having to factor it. The innovative concept of this new method is finding 2 fractions knowing their product (c/a) and their sum (-b/a). This new method is applicable to any quadratic equation that can be factored. It can replace the existing trial-and-error factoring method since this last one contains too many more permutations. In general, it is hard to tell in advance if a given quadratic equation can be factored. However, if the new method fails to get the answers, then you can positively conclude that this equation can not be factored. Consequently, the quadratic formula must be used in solving. We advise students to always try to solve the given equation by the new method first. If the student gets conversant with this method, it usually take less than 2 trials to get answers. 2. the second one uses the quadratic formula that students can find in any algebra book. This formula must be used for all quadratic equations that can not be factored.
How does 2x squared minus x equal one half?
2x²-x=0.5 is more manageable in the standard quadratic form : 2x2 - x - 0.5 = 0double this to get rid of that pesky 0.5 : 4x2 - 2x -1 = 0The quadratic formula solves ax2 + bx + c =0 using x = (-b +/- (b2-4ac) 0.5 ) / 2ax equals [minus b plus or minus (square root of {b squared minus 4ac})] all over 2aputting in a=4, b=-2, c=-1 gives (2 +/- (4 + 16)0.5 ) / 8which reduces to( 1 +/- (5)0.5) / 4this evaluates to x= .809 or -.309Notice that plus or minus square root (b2 - 4ac) usually produces two different solutions. Equations in the second degree always have two solutions; if the quadratic is such that b2 equals 4ac the formula seems to give only one solution. Don't worry about this; there are still two solutions, they just happen to be identical!
What does it mean in algebra to complete the square?
A quadratic equation can be solved by completing the square which gives more information about the properties of the parabola than with the quadratic equation formula.
When using the quadratic formula x always has multiple correct solutions?
Not necessarily. Formula gives two values but they can be identical.
Is there a solution to the quadratic equation of 3x squared -10x equals -5?
Yes because rearranging it into the form of 3x2-10x+5 = 0 makes the discriminant of the quadratic equation greater than zero which means it will have two different solutions. Solving the equation by means of the quadratic formula gives x as being 2.721 or 0.613 both corrected to 3 decimal places.
Simplify 2t squared plus 8t plus 5 equals 0?
2t2+8t+5 = 0 The expression in this quadratic equation is not so simple to factorise because 5 is a prime number which has only two factors (itself and one) but we can get a near enough solution by using the quadratic equation formula. Using the quadratic equation formula gives the solution as: t = - 0.7752551286 or t = - 3.224744871
What are the solutions to x squared minus twelve x plus sixteen equals zero?
Quadratic formula gives roots as 1.53 and 10.47 (to nearest hundredth.)
What is the third step in solving this equation by completing the square?
Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by several methods including factoring, graphing, using the square roots or the quadratic formula. Completing the square will always work when solving quadratic equations and is a good tool to have. Solving a quadratic equation by completing the square is used in a lot of word problems.I want you to follow the related link that explains the concept of completing the square clearly and gives some examples. that video is from brightstorm.
What are some examples of how to use the quadratic formula?
For a quadratic equation in the form: ax² + bx + c = 0 The quadratic formula comes from completing the square of the quadratic equation that gives you a result of x=-b±√b²-4ac divided by 2a. Using a simple quadratic equation like x² + 2x + 1 = 0 a=1; b=2; c=1 x=-2±√2²-4(1)(1) divided by 2a x=-2±√4-4 divided by 2a (4 - 4 = 0 and the square root of 0 is 0) Therefore, x=-2
What is -16t2 plus 70t - 65?
There are no integer roots of this equation. Using the quadratic formula gives roots of 1.34 and 3.04 plus or minus loose change in each case.
How are the sum and product of the solutions of a quadratic equation related to the coefficients of the equation?
If you have a quadratic, which is factored like (x - P)(x - Q) = 0, so P & Q are solutions for x. Multiplying the binomials gives: x2 - Px - Qx + PQ = 0 ---> x2 - (P+Q)x + PQ = 0, so the negative of the sum is the coefficient of the x term, and the product is the constant term (no variable x).
How do you solve complex cases of quadratic equations?
If the discriminant - the part under the radical sign in the quadratic formula - is negative, then the result is complex, it is as simple as that. You can't convert a complex number to a real number. If a particular problem requires only real-number solutions, then - if the formula gives complex numbers - you can state that there is no solution.
What is the quadratic equation with the solutions -1 an 5?
The equation must have roots of x = -1 and x = 5 So: x + 1 = 0 and x - 5 = 0 Therefore: (x + 1)(x - 5) = 0 Expanding the brackets gives the equation: x2 - 4x - 5 = 0
What is the point of intersection of the line y equals 2x plus 5 over 4 with the curve y squared equals 10x?
Point of intersection: (5/8, 5/2) Square both sides of the first equation and merge it with the second equation to form a quadratic equation:- 4x2-5x+25/16 = 0 Solving the above using the quadratic equation formula gives x as having two poitive roots of 5/8 and substituting this into the linear equation gives y a value of 5/2.
