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The second of two numbers is 4 times the first their sum is 45?
This problem asks us to find 2 numbers, n1 and n2, with the following relations between them: * n2 = 4 n1 * n1 + n2 = 45 Substituting the first equation into the second one gives us: * n1 + 4n1 = 45 which gives us * n1 = 9. We can now use this solution to find n2 with the first equation * n2 = 4 n1 = 36 So the first number is 4, the second number is 36.
What does 42 decreased by twice a number means?
If you have a number x, then twice that number is 2*x and so the expression means 42 - 2*x
What is the equation for the number of diagonals that can be formed in a polygon?
The equation is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
What does the number 2 mean in MgCl2?
The number 2 means that there are 2 chlorine atoms attached to one magnesium atom in a molecule of magnesium chloride
What is the number of distinguishable permutations?
The formula for finding the number of distinguishable permutations is: N! -------------------- (n1!)(n2!)...(nk!) where N is the amount of objects, k of which are unique.
How many diagonals does a polygon with 38 sides have?
1/2*(n2-3n) = 665 diagonals where n means number of sides
What is the number of atoms of nitrogen of .755 mol of N2?
There are 9.06 x 10^22 atoms of nitrogen in 0.755 mol of N2. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of N2 (.755 mol) and the number of nitrogen atoms in one molecule of N2 (2 atoms).
What is oxidation number for N2?
0 in N2
How many atoms does N2 have?
It has two atoms. Hence the two after the N.
What is the oxidation number for N2?
0 in N2
What will be the number of orbitals for n shells?
Each shell has a total of n2 orbitals, where n is the principal quantum number. For N shells the total orbitals is therefore :- N2 + (N-1)2 + (N-2)2 +....+1
What is the formula for the number of diagonals?
1/2*(n2-3n) where n is the number of sides of the polygon.
How many sides does a polygon have if it has 902 diagonals?
Let n be the number of sides: 1/2*(n2-3n) = diagonals 1/2*(n2-3n) = 902 Multiply both sides by 2 and form a quadratic equation: n2-3n-1804 = 0 Solving the above by means of the quadratic equation formula gives a positive value for n as 44 Therefore the polygon has 44 sides
How do your use triangular numbers to make square numbers?
The sum of any two successive triangular number is a square number.The nth triangular number is n(n+1)/2 = (n2 +n)/2The next triangular number is (n+1)*(n+2)/2 = (n2 + 3n + 2)/2Their sum is (2n2 + 4n + 2)/2 = n2 + 2n + 1 = (n + 1)2This is easy to visualise. For example T3 + t4 = 42[T3, the 3th triangular number represented by X,t4, the 4th triangular number represented by x]XXX_____xXX_____xxX_____xxx_____xxxxBring them together and you have:XXXxXXxxXxxxxxxxThe sum of any two successive triangular number is a square number.The nth triangular number is n(n+1)/2 = (n2 +n)/2The next triangular number is (n+1)*(n+2)/2 = (n2 + 3n + 2)/2Their sum is (2n2 + 4n + 2)/2 = n2 + 2n + 1 = (n + 1)2This is easy to visualise. For example T3 + t4 = 42[T3, the 3th triangular number represented by X,t4, the 4th triangular number represented by x]XXX_____xXX_____xxX_____xxx_____xxxxBring them together and you have:XXXxXXxxXxxxxxxxThe sum of any two successive triangular number is a square number.The nth triangular number is n(n+1)/2 = (n2 +n)/2The next triangular number is (n+1)*(n+2)/2 = (n2 + 3n + 2)/2Their sum is (2n2 + 4n + 2)/2 = n2 + 2n + 1 = (n + 1)2This is easy to visualise. For example T3 + t4 = 42[T3, the 3th triangular number represented by X,t4, the 4th triangular number represented by x]XXX_____xXX_____xxX_____xxx_____xxxxBring them together and you have:XXXxXXxxXxxxxxxxThe sum of any two successive triangular number is a square number.The nth triangular number is n(n+1)/2 = (n2 +n)/2The next triangular number is (n+1)*(n+2)/2 = (n2 + 3n + 2)/2Their sum is (2n2 + 4n + 2)/2 = n2 + 2n + 1 = (n + 1)2This is easy to visualise. For example T3 + t4 = 42[T3, the 3th triangular number represented by X,t4, the 4th triangular number represented by x]XXX_____xXX_____xxX_____xxx_____xxxxBring them together and you have:XXXxXXxxXxxxxxxx
What is the oxidation number of N 2?
The oxidation number of N in N2 is 0 since it is in its elemental form. In a diatomic molecule like N2, each nitrogen atom has an oxidation number of 0.
Four times the square of a number is 16?
4*n2 = 16 Divide both sides by 4: n2 = 4 Take square roots: n = -2 or n = 2
What is two times a number?
double the number n2 2n 2xn nx2
