It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
Formula: 0.5*(n2-3n) and n is the number of sides 0.5*(462-138) = 989 diagonals
The formula used to find the number of diagonals in a polygon is n(n-3)/2. 30 x 27/2 = 810/2 = 405 diagonals.
Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon
Number of sides - 2
The formula is: 0.5*(n2-3n) = number of diagonals when n is the number of sides of the polygon
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
n side polygon has n(n-3)/2 diagonals therefore a hexagon has 9 diagonals
1/2*(n2-3n) = number of diagonals Rearranging the formula: n2-3n-(2*diagonals) = 0 Solve as a quadratic equation and taking the positive value of n as the number of sides.
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
1/2*(n2-3n) = diagonals when n equals number of sides.
For a 9 sided polygon it is: 0.5*(92-(3*9)) = 27 diagonals
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
If it has 28 sides then it has 350 diagonals by using the formula 0.5(n^2 -3n) whereas 'n' means number of sides