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What is the area of a rectangle with a diagonal of 15 and a length of 9?
Wiki User
∙ 11y ago
Diagonal = 15 and Length = 9 units.
Therefore, by Pythagoras, Breadth = sqrt(152 - 92) = sqrt(144) = 12 units.
So area = 9*12 = 108 sq units.
Diagonal = 15 and Length = 9 units.
Therefore, by Pythagoras, Breadth = sqrt(152 - 92) = sqrt(144) = 12 units.
So area = 9*12 = 108 sq units.
Diagonal = 15 and Length = 9 units.
Therefore, by Pythagoras, Breadth = sqrt(152 - 92) = sqrt(144) = 12 units.
So area = 9*12 = 108 sq units.
Diagonal = 15 and Length = 9 units.
Therefore, by Pythagoras, Breadth = sqrt(152 - 92) = sqrt(144) = 12 units.
So area = 9*12 = 108 sq units.
Wiki User
∙ 11y ago
Wiki User
∙ 11y agoDiagonal = 15 and Length = 9 units.
Therefore, by Pythagoras, Breadth = sqrt(152 - 92) = sqrt(144) = 12 units.
So area = 9*12 = 108 sq units.
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