B(1,-5)
Coordinates are what tells you where a "point" is on a coordinate plane. For instance, Point A may be at (4, 6) when Point B is at (-2, 5)
Oh, dude, Point B's coordinates are like the address for that point on a graph. It's just a pair of numbers that tells you where it is hanging out. So, like, if Point B is at (3, 5), it's basically chilling at the spot where the x-coordinate is 3 and the y-coordinate is 5. Easy peasy, right?
Well if you have found the derivative (slope of the tangent line) of the curve at that point and you know the xy coordinates for that point in the curve then you set it up in y=mx+b format where y is your y-coordinate, x is your x-coordinate and m is your derivative and solve for b
The quadrant where a point has a negative x coordinate and a negative y coordinate is located in quadrant 3.
The axes of coordinate planes intersect at the point of origin.
If you mean end point A is (3, 5) and midpoint of line AB is (-2, 8) then end point B is (-7, 11)
To find the coordinates of an image reflected over the line ( y = x ), you simply swap the x-coordinate and y-coordinate of the original point. For a point ( (a, b) ), the reflected image will have the coordinates ( (b, a) ). This rule applies to any point in the Cartesian coordinate system.
Coordinates are what tells you where a "point" is on a coordinate plane. For instance, Point A may be at (4, 6) when Point B is at (-2, 5)
Oh, dude, Point B's coordinates are like the address for that point on a graph. It's just a pair of numbers that tells you where it is hanging out. So, like, if Point B is at (3, 5), it's basically chilling at the spot where the x-coordinate is 3 and the y-coordinate is 5. Easy peasy, right?
A function that translates a point ((x, y)) to the right by (a) units and up by (b) units can be expressed as (f(x, y) = (x + a, y + b)). This means you simply add (a) to the x-coordinate and (b) to the y-coordinate of the original point. In function notation, if (f(x, y)) represents the original point, the translated point can be represented as (f'(x, y) = (x + a, y + b)).
First find the length between the midsegment point and coordinate B. The difference between 0 and -3 is 3. Thus, half the line is 3. So, to get to A, we have to go 3 in the other direction. -3 and 3 more would make Coordinate A land on (-6,2)
The x and y coordinates swap places. Thus, the point (a,b) becomes (b, a).
Well if you have found the derivative (slope of the tangent line) of the curve at that point and you know the xy coordinates for that point in the curve then you set it up in y=mx+b format where y is your y-coordinate, x is your x-coordinate and m is your derivative and solve for b
To determine if a point is on a line, you can substitute the coordinates of the point into the equation of the line. If the equation holds true after substitution, the point lies on the line. For example, for a line defined by (y = mx + b), if you plug in the x-coordinate of the point and the resulting y-value matches the y-coordinate of the point, then it is on the line. Otherwise, the point is not on the line.
The coordinate of what?
What is used to locate a point in a coordinate plane
The 'x' coordinate of B is the average of the 'x' coordinates of A and C. The 'y' coordinate of B is the average of the 'y' coordinates of A and C.