It is probably 2.
No, it has factors... 4x2 + 8x -21 = (2x+7)(2x-3)
4x2+8x+3 ------> (2x+3)(2x+1)
1/2 , 3/2
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
We began by assuming that the 4 odd integers are consecutive, and everythingworked just fine. So, although there may well be more than one correct answer tothe question as it's stated, we have a hunch they're supposed to be consecutive,and that detail was accidentally left out of the question.Call the 4 consecutive odd integers (2x - 3), (2x - 1), (2x + 1), and (2x + 3).Product of the two larger ones = (4x2 + 8x + 3)Product of the two smaller ones = (4x2 - 8x + 3)Smaller product + 112 = larger product . . . . . (4x2 - 8x + 3) + 112 = (4x2 + 8x + 3)Eliminate parentheses . . . . . 4x2 - 8x + 115 = 4x2 + 8x + 3Subtract (4x2 + 3) from each side . . . . . -8x + 112 = 8xAdd 8x to each side . . . . . 112 = 16xDivide each side by 16 . . . . . x = 7The consecutive odd integers are: 11, 13, 15, and 17.Check:11 x 13 = 14315 x 17 = 255255 - 143 = 112 Yippee!
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
4x2-8x-9y2+54x=113(4x2-8x ) + (-9y2+54y ) =1134(x2-2x+1) -9(y2-6y+9) =113+4-81 because of distribution4(x-1)2 - 9(y-3)2 = 36Divide by 36(x-1)2 - (y-3)2 =19 4
4x2 + 6x - 3 (with no remainder)
4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2
You can find it by taking the derivative of the function and solving for zero: y = -4x2 - 24x - 29 ∴ y' = -8x - 24 Let y' = 0: 0 = -8x - 24 8x = -24 x = -3 Now you can plug that x value into the original equation to get it's corresponding y co-ordinate: y = 4(-3)2 - 24(-3) - 29 ∴ y = 27 + 72 - 29 ∴ y = 70 So the vertex is at the point {-3, 70}
Fifth degree - the highest power of x that appears.