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use the chain rule and product rule: f(x)=1/u(x), f'(x)=-1/u2(x)*u'(x) and f(x)=a(x)b(x), f'(x)=a'(x)b(x)+b'(x)a(x)
the derivative of sin is cos, and the derivative of cos in negative sin.
so f(x)=1/(sin(x)cos(x)), f'(x)=-1/(sin(x)cos(x))2*(cos2(x)-sin2(x))
or assume sin(x)cos(x)=.5sin(2x)
so using chain rule, f'(x)=-2/sin2(2x)*.5cos(2x)*2. Both answers are equivalent.
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What is the derivative of 1 divided by sinx?
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What is sin 3x in terms of sin x?
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What is the value of sinX wrt cosX?
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