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You can use the Pythagorean Theorem to calculate the distance between two points. The distance is the square root of ((difference in x-coordinates)2 + (difference in y-coordinates)2).
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The distance is the diagonal of a right angled triangle with equal two side and each equal 6.
So, the distance is:
(36 + 36)1/2 = 6 x 1.4142 = 8.4853
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What is the distance from Point A (-2 -1) to Point B (-8 -7)?
The x distance is (-2-(-8)) = 6 The y distance is (-1-(-7)) = 6 The point to point distance is from Pythagorean theorem square root of (x squared +y squared) = 8.485
What is the distance between the points 3 and 7 and -3 and -1?
The distance between (3, 7) and (-3, -1) is sqrt{[(3 - (-3)]2 + [7 - (-1)]2} = sqrt{[3 + 3]2 + [7 + 1]2} =sqrt{[6]2 + [8]2} = sqrt{36 + 64} = sqrt{100} = 10 units.
What is the distance between the numbers 1 and 7?
6?! 1-2 2-3 3-4 4-5 5-6 6-7
What slope of the line that contains the points (7-1) and (-2-4)?
m = ( y(1) - y(2)) / ( x(1) - x(2)) For the point ( 7 , -1) & ( -2 , -4) m = ( -1- - 4) / ( 7 --2) m = ) -1 + 4)/( 7 + 2) m = (3)/(9) m = 1/3 The slope!!!! 2,-4)
If Devin throws a football 7 and a third yards and Carl throws it 2 and a half times farther than Devin then how much farther did Carl's throw travel than Devin's?
The answer is the difference between the lengths, which is 11 yards (or 33 feet).To find the answerIt is easier to first express the first distance in feet and eliminate the fraction.7 1/3 yards x 3 = 22 feetTo find the second distance, multiply by 2 1/2. (22 x 2 1/2 = 55 feet)Subtract to find the difference 55-22 = 33 feet, which is 33/3 or 11 yards.To find the answer by multiplying fractions (which is the point of the problem)The second distance, the distance Carl threw the ball, is 7 1/3 x 2 1/2.To multiply mixed fractions (like 7 1/3), it's a good idea to convert them to improper fractions first. 7 1/3 = 22/3 and 2 1/2 = 5/222/3 x 5/2 = 110/6 = 18 2/6 yards = 18 1/3 yards (55 feet).Subtracting Devin's distance, 18 1/3 - 7 1/3 = 11 yards (33 feet).
What is the distance from Point A (-2 -1) to Point B (-8 -7)?
The x distance is (-2-(-8)) = 6 The y distance is (-1-(-7)) = 6 The point to point distance is from Pythagorean theorem square root of (x squared +y squared) = 8.485
What is the distance between point j and point kJ point is -4 -7 k's point is 2 1?
djk = [ ( xj - xk )^2 + ( yj - yk )^2 ]1/2djk = [ ( 2 - -4 )^2 + ( 1 - -7 )^2 ]^1/2djk = [ ( 6 )^2 + ( 8 )^2 ]^1/2djk = [ 36 + 64 ]^1/2 = [ 100 ]^1/2 = 10
Distance between point A 5 7 and point B 2 4?
|AB| = sqrt[(5 - 2)2 + (7 - 4)2] =sqrt[9 + 9] = 3*sqrt(2)
What is the distance between the points -2 1 and 3 7?
58 * * * * * No. Distance squared = (-2 - 3)2 + (1 - 7)2 = 52 + 62 = 25 + 36 = 61 So distance = sqrt(61) = 7.8 approx.
What is the distance between 7 1 and 7 3 on a coordinate plane?
The distance between two points on a coordinate plane is calculated using the distance formula: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, the coordinates of the two points are (7, 1) and (7, 3). Since the x-coordinates are the same, we only need to calculate the difference in the y-coordinates, which is (3 - 1) = 2. Plugging this into the distance formula gives us: Distance = √((0)^2 + (2)^2) = √4 = 2. Therefore, the distance between the two points is 2 units.
What is the perpendicular distance from the point 7 and 5 to the straight line equation of 3x plus 4y minus 16 equals 0?
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point: (7, 5) Equations intersect: (4, 1) Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5
What is the distance between the points 3 and 7 and -3 and -1?
The distance between (3, 7) and (-3, -1) is sqrt{[(3 - (-3)]2 + [7 - (-1)]2} = sqrt{[3 + 3]2 + [7 + 1]2} =sqrt{[6]2 + [8]2} = sqrt{36 + 64} = sqrt{100} = 10 units.
What is the perpendicular distance from the point of 7 5 to the straight line whose equation is 3x plus 4y minus 16 equals 0?
Straight line equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Point of intersection: (4, 1) Distance: (7-4)2+(5-1)2 = 25 and the square root of this is the perpendicular distance which is 5 units of measurement
What is the distance between -2 1 and 3 7?
58
What is the distance between 7 0 and 8 0?
(8-7)2+(0-0)2 = 1 and the square root of 1 is 1 Answer: 1
What is the distance between the points 4 7 and 7 8?
The Pythagorean distance is sqrt[(4 - 7)2 + (7 - 8)2] = sqrt[9 + 1] = sqrt(10) = 3.162 approx.
What is the distance between Sudbury and Dryden Ont?
7 1/2
