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How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
What is perpendicular to y equals 2x-4?
6
How do you find the unit rate to y-2x?
The question contains an expression, not an equation. An expression cannot have a unit rate.
Find equation perpendicular to given line contain given point?
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
Find the slope of the line perpendicular to the line y equals 2x plus 1?
The slope of the perpendicular is -(1/2) .
Find the equation of a straight line perpendicular to the line 4y-3x12?
There are infinitely many lines perpendicular to this line. All of them have the slope of -4/3, if that fact is of any help to you.
Find the equation of the line perpendicular when the slope is zero?
when the slope is 0, the graph is a horizontal line on the x axis so the y axis is perpendicular to it, which can be written x=0
What is an equation for a line perpendicular to y4x 3 that passes through the point (-85)?
To find the equation of a line perpendicular to ( y = 4x + 3 ), we first determine the slope of the given line, which is 4. The slope of a line perpendicular to it is the negative reciprocal, so it would be ( -\frac{1}{4} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with the point (-8, 5) and the slope ( -\frac{1}{4} ), the equation becomes ( y - 5 = -\frac{1}{4}(x + 8) ). Simplifying this gives the equation of the perpendicular line.
How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
Which equation is a line that is perpendicular to the line of 8x 1 algebra 2?
To find a line that is perpendicular to the line represented by the equation (8x + b) (assuming (b) is a constant), we first need to determine the slope of the original line. The slope of the line (y = 8x + b) is 8. The slope of a line that is perpendicular to this would be the negative reciprocal, which is (-\frac{1}{8}). Therefore, a possible equation for a line perpendicular to it could be (y = -\frac{1}{8}x + c), where (c) is any constant.
What is the perpendicular equation that meets the line of 2 3 and 5 7 at its midpoint showing key aspects of work?
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
What is perpendicular to y equals 2x-4?
6
What equation is perpendicular to y-8x-6?
To find an equation that is perpendicular to ( y - 8x - 6 = 0 ), we first determine the slope of the given line. Rearranging it to slope-intercept form ( y = 8x + 6 ) reveals that the slope is 8. The slope of a line perpendicular to this would be the negative reciprocal, which is ( -\frac{1}{8} ). Therefore, an equation perpendicular to the original line can be expressed in point-slope form as ( y - y_1 = -\frac{1}{8}(x - x_1) ), where ( (x_1, y_1) ) is any point on the original line.
What is the equation of the line that contains the points -32 and 5-5?
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
What is an equation that contains at least one variable?
An equation that contains at least one variable is (2x + 5 = 15). In this equation, (x) is the variable, and the equation states that when you multiply (x) by 2 and add 5, the result equals 15. Solving for (x) will allow you to find its value.
The equation of a line is x Minus 3y Plus 2 Equals 4. Which line is perpendicular to this line?
x-3y+2 = 4 -3y = -x+4-2 -3y = -x+2 y = 1/3x-2/3 Slope or gradient of the perpendicular line is -3 Use y-y1 = -3(x-x1) to find the perpendicular equation
What equation has a graph perpendicular to y equals 2x-3?
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