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What is the perpendicular equation of line -9x-2y=2 through a point (-8,5)
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
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The question contains an expression, not an equation. An expression cannot have a unit rate.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
The slope of the perpendicular is -(1/2) .
There are infinitely many lines perpendicular to this line. All of them have the slope of -4/3, if that fact is of any help to you.
when the slope is 0, the graph is a horizontal line on the x axis so the y axis is perpendicular to it, which can be written x=0
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
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THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
x-3y+2 = 4 -3y = -x+4-2 -3y = -x+2 y = 1/3x-2/3 Slope or gradient of the perpendicular line is -3 Use y-y1 = -3(x-x1) to find the perpendicular equation
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Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
First, convert the equation to Slope-Intercept Form (y = mx + b) m = slope b = y-intercept 3x - 4y = 8 Subtract 3x from both sides of the equation. -4y = -3x + 8 Divide the entire equation by -4. y = 3/4x -2 Now that we know that the slope is 3/4, we can convert it to its perpendicular slope. The perpendicular slope is the opposite reciprocal of the original slope. In order to find it, we flip the fraction and change the sign. Original Slope: 3/4 Perpendicular Slope: -4/3
The equation 5x -2y = 3 is the same as y = 2.5x -1.5 The perpendicular slope or gradient is the negative reciprocal of 2.5 which is minus 1/2.5 To find the perpendicular equation use y -y1 = m(x -x1) and the point (3, -4) y - (-4) = -1/2.5(x -3) y = -1/2.5x +6/5 -4 y = -1/2.5x -14/5 which can be rearranged in the form of 2x +5y +14 = 0
First find the mid-point of the line segment which will be the point of intersection of the perpendicular bisector. Then find the slope or gradient of the line segment whose negative reciprocal will be the perpendicular bisector's slope or gradient. Then use y -y1 = m(x -x1) to find the equation of the perpendicular bisector. Mid-point: (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope or gradient: 3q-q/7p-p = 2q/6p = q/3p Slope of perpendicular bisector: -3p/q Equation: y -2q = -3p/q(x -4p) y = -3px/q+12p2/q+2q Multiply all terms by q to eliminate the fractions: qy = -3px+12p2+2q2 Which can be expressed in the form of: 3px+qy-12p2-2q2 = 0