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How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
What is perpendicular to y equals 2x-4?
6
How do you find the unit rate to y-2x?
The question contains an expression, not an equation. An expression cannot have a unit rate.
Find equation perpendicular to given line contain given point?
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
Find the slope of the line perpendicular to the line y equals 2x plus 1?
The slope of the perpendicular is -(1/2) .
Find the equation of a straight line perpendicular to the line 4y-3x12?
There are infinitely many lines perpendicular to this line. All of them have the slope of -4/3, if that fact is of any help to you.
Find the equation of the line perpendicular when the slope is zero?
when the slope is 0, the graph is a horizontal line on the x axis so the y axis is perpendicular to it, which can be written x=0
How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
What is the perpendicular equation that meets the line of 2 3 and 5 7 at its midpoint showing key aspects of work?
Here are the key steps:* Find the midpoint of the given line. * Find the slope of the given line. * Divide -1 (minus one) by this slope, to get the slope of the perpendicular line. * Write an equation for a line that goes through the given point, and that has the given slope.
What is the equation of the line that contains the points -32 and 5-5?
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
What is perpendicular to y equals 2x-4?
6
The equation of a line is x Minus 3y Plus 2 Equals 4. Which line is perpendicular to this line?
x-3y+2 = 4 -3y = -x+4-2 -3y = -x+2 y = 1/3x-2/3 Slope or gradient of the perpendicular line is -3 Use y-y1 = -3(x-x1) to find the perpendicular equation
What equation has a graph perpendicular to y equals 2x-3?
5
What is the perpendicular distance from the point of 7 and 5 that meets the straight line equation of 3x plus 4y equals 0 on the Cartesian plane showing work?
Equation: 3x+4y = 0 => y = -3/4x Perpendicular slope: 4/3 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (2.08, -1.56) Distance from (7, 5) to (2.08, -1.56) = 8.2 units using the distance formula
What is 3x - 4y equals 8 perpendicular to?
First, convert the equation to Slope-Intercept Form (y = mx + b) m = slope b = y-intercept 3x - 4y = 8 Subtract 3x from both sides of the equation. -4y = -3x + 8 Divide the entire equation by -4. y = 3/4x -2 Now that we know that the slope is 3/4, we can convert it to its perpendicular slope. The perpendicular slope is the opposite reciprocal of the original slope. In order to find it, we flip the fraction and change the sign. Original Slope: 3/4 Perpendicular Slope: -4/3
How do you find the straight line equation that passes through the point 3 -4 and is perpendicular to the line 5x -2y equals 3?
The equation 5x -2y = 3 is the same as y = 2.5x -1.5 The perpendicular slope or gradient is the negative reciprocal of 2.5 which is minus 1/2.5 To find the perpendicular equation use y -y1 = m(x -x1) and the point (3, -4) y - (-4) = -1/2.5(x -3) y = -1/2.5x +6/5 -4 y = -1/2.5x -14/5 which can be rearranged in the form of 2x +5y +14 = 0
How do you work out and find the perpendicular bisector equation meeting the straight line segment of p q and 7p 3q?
First find the mid-point of the line segment which will be the point of intersection of the perpendicular bisector. Then find the slope or gradient of the line segment whose negative reciprocal will be the perpendicular bisector's slope or gradient. Then use y -y1 = m(x -x1) to find the equation of the perpendicular bisector. Mid-point: (7p+p)/2 and (3q+q)/2 = (4p, 2q) Slope or gradient: 3q-q/7p-p = 2q/6p = q/3p Slope of perpendicular bisector: -3p/q Equation: y -2q = -3p/q(x -4p) y = -3px/q+12p2/q+2q Multiply all terms by q to eliminate the fractions: qy = -3px+12p2+2q2 Which can be expressed in the form of: 3px+qy-12p2-2q2 = 0
