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name the first integer "x" and the second one "y" with y=x+1 (y is the next integer after x, i.e. the next bigger) So the equation would be: 3x=2y+4 now put x+1 for y and you get: 3x=2x+6

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Q: What is the equation you would use to find 2 consecutive integers such that three times the first is four more than twice the second?
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How do you find consecutive integers?

Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3


The sum of two consecutive integers is -377 What are the integers?

Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188


How Find three consecutive even integers such that three times the first integer is six more than twice the second integer?

The numbers are 14, 16 and 18.


The product of 2 consecutive integers is 156?

12 x 13 = 156 How to find the answer: If x is the first integer, then x+1 is the next consecutive integer. so x(x+1) = 156 or x^2 + x -156 =0 solve the quadratic equation for x.


If the sum of the first two of the five consecutive odd integers is 52what is the sum of the last two integers?

Let the first odd integer be x, then the second one is x + 2. So we have: x + (x + 2) = 52 2x + 2 = 52 subtract 2 to both sides 2x = 50 divide by 2 to both sides x = 25 Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33. So the sum of the last two integers is 64 ( 31 + 33).

Related questions

What is the equation for this The sum of two consecutive integers in 71?

Let x represent the first integer. The second consecutive integer is then x + 1. The equation can be written as x + (x + 1) = 71.


FIND Three consecutive integers such that the sum of the second and the third is 17 Which equation would be used to solve this word problem?

If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.


The sum of two consecutive even integers is 50 what is the first number?

24. The second is 26.


What three consecutive integers have a sum of 43?

Let x be the first integer. Then the sum of the three consecutive integers is x + (x+1) + (x+2), which equals 3x + 3. We are given that this sum is 43, so we can write the equation 3x + 3 = 43. Solving this equation, we find that x = 13. Therefore, the three consecutive integers are 13, 14, and 15.


How do you find consecutive integers?

Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3


The sum of two consecutive integers is -377 What are the integers?

Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188


Three conecutive integers whos sum is 117?

You can find those by trial and error. You can also write an equation for the three consecutive integers, and solve it. If the first number is "n", the others are "n + 1" and "n + 2". By solving the equation for "n", you get the first of the three numbers.


What is the sum of the first four non-negative consecutive even integers?

The sum of the first four non-negative, consecutive, even integers is 20.


What three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer?

10-11-12


What are the 2 consecutive integers such that the sum of one-third the first and one-fourth the second is 9?

-7


The sum of 3 consecutive even integers is 54 What is the first consecutive integer?

The first integer is 17.


Three consecutive odd integers such that four times the sum of the first and second is 7 less than 7 times the third?

Let's call the smallest of the consecutive odd integers x. Then the other ones are x+2 and x+4 respectively, and your equation becomes 4*(x+x+2)+7 = 7*(x+4) which is equivalent to 8x+15=7x+28 or x=13, so the consecutive integers you're looking for are 13, 15 and 17.