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There are infinitely many polynomials of order 4 (or higher) that will give these as the first four numbers and any one of these could be "the" rule. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest rule is a linear polynomial U(n) = 6*(2 - n) for n = 1 , 2, 3, ...
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Jordan6n - c = 0
When n = 2
-6(2) - c = 0
-12 -c = -
c = 12
Verification when n = 3
-6(3) + 12 =
-18 + 12= -6 As agreed.
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What is the nth term of this sequence 2 8 18 32 50?
The nth term is 2n2. (One way to find that is to notice at all the numbers are even, then divide them by 2. The sequence becomes 1, 4, 9, 16, 25, which are the square numbers in order.)
What is the sequence of 10 8 6 4?
10-2x for x = 0, 1, 2, 3, ... Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.
What Is the nth term of the number sequence 15 12 9 6?
According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. Conversely, it is possible to find a rule such that any number of your choice can be the next one.The simplest rule is un = 18 - 3n
What is the answer to this number sequence 0 12 72 240 600 1260 2352?
There can be no answer because a number sequence, in itself, is not a question.
What is the nth term of 2 8 16 26 38 52?
n2 + 3n - 2
