n2 + 3n - 2
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
There are infinitely many possible answers. Given ANY number, it is always possible to find a polynomial of order 5 [at most] that can be used as the nth term rule for the given five number and the additional sixth. There are also non-polynomial solutions. Each different sixth number will result in a different polynomial and, since there are infinitely many sixth numbers, there are infinitely many answers to the question. Having said that, the simplest polynomial solution is Un = 9n - 2
Sn = -8n + 2S0 = -8(0) + 2 = 2S1 = -8(1) + 2 = -6S2 = -8(2) + 2 = -14S3 = -8(3) + 2 = -22S4 = -8(4) + 2 = -30S5 = -8(5) + 2 = -38
It depends on the speed you are going.
Given that the effective limit on the number characters on a license plate is 7, and that each of those characters could be a letter (26 possibilities), a number (10 more possibilities, 36 total), a hyphen (37 total), or a space (38 total possibilities), the total number of possible license plates is 38^7 or 38*38*38*38*38*38*38 which is 114,415,582,592
2 + ((6 + 2 * (n - 1) * (n - 1))
[ 6n + 8 ] is.
Each number is increasing by increments of 8 10 12 14 ... etc and so the next number will be 52+16 = 68
It depends what the next number in the sequence is. The simplest polynomial for those 5 terms is: U{n} = n² + 3n - 2
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term of the sequence is (n + 1)2 + 2.
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
58
If the term number is n, then the nth term is 10(n-1) +8.
The given sequence is an arithmetic sequence with a common difference that increases by 1 with each term. To find the nth term of an arithmetic sequence, you can use the formula: nth term = a + (n-1)d, where a is the first term, n is the term number, and d is the common difference. In this case, the first term (a) is 3 and the common difference (d) is increasing by 1, so the nth term would be 3 + (n-1)(n-1) = n^2 + 2.