nth term = n*(n+2)+(n-2) when
1st term = 2; 2nd term = 8; 3rd term = 16; 4th term = 26; 5th term = 38; 6th term = 52
Step 1: look at n=3 and 4 and try to come up with a formula that is close
Step 2: first try multiplication for n=3 which should be 16 which is close to 3x5; for n=4 it should be 26 which is close to 4x6
Step 3: so the first part that works is n(n+2) but this only gets us close, not exact
Step4: for n=3 which is 16 is n(n+2)+1; for n=4 it is 26 which is n(n+2)+2
Step 5: so now we can try n(n+2)+(n-2). We test this for n=5 which is 38. 5(5+2)+(5-25) = 38. Test again for n=6 which is 52. 6(6+2)+(6-2) = 52...so all good.
To find the pattern in the sequence 2, 8, 16, 26, 38, 52, we can see that the differences between consecutive terms are increasing by 6, 8, 10, 12, and 14. This indicates that the sequence is following a quadratic pattern. By calculating the second differences, we find that they are constant at 2. Therefore, the nth term of this sequence can be expressed as n^2 + 1.
The given sequence appears to follow a pattern. Let's analyze the differences between consecutive terms:
8 - 2 = 6
16 - 8 = 8
26 - 16 = 10
38 - 26 = 12
52 - 38 = 14
The differences between consecutive terms are increasing by 2 each time. So, to find the next term in the sequence, add 16 (the previous difference) and 2:
14 + 2 = 1614+2=16
Now, add this difference to the last term in the sequence:
52 + 16 = 6852+16=68
Therefore, the next term in the sequence is 68.
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
There are infinitely many possible answers. Given ANY number, it is always possible to find a polynomial of order 5 [at most] that can be used as the nth term rule for the given five number and the additional sixth. There are also non-polynomial solutions. Each different sixth number will result in a different polynomial and, since there are infinitely many sixth numbers, there are infinitely many answers to the question. Having said that, the simplest polynomial solution is Un = 9n - 2
Sn = -8n + 2S0 = -8(0) + 2 = 2S1 = -8(1) + 2 = -6S2 = -8(2) + 2 = -14S3 = -8(3) + 2 = -22S4 = -8(4) + 2 = -30S5 = -8(5) + 2 = -38
It depends on the speed you are going.
Given that the effective limit on the number characters on a license plate is 7, and that each of those characters could be a letter (26 possibilities), a number (10 more possibilities, 36 total), a hyphen (37 total), or a space (38 total possibilities), the total number of possible license plates is 38^7 or 38*38*38*38*38*38*38 which is 114,415,582,592
2 + ((6 + 2 * (n - 1) * (n - 1))
[ 6n + 8 ] is.
Each number is increasing by increments of 8 10 12 14 ... etc and so the next number will be 52+16 = 68
It depends what the next number in the sequence is. The simplest polynomial for those 5 terms is: U{n} = n² + 3n - 2
The nth term in the arithmetic progression 10, 17, 25, 31, 38... will be equal to 7n + 3.
The nth term of the sequence is (n + 1)2 + 2.
9n+2
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
58
If the term number is n, then the nth term is 10(n-1) +8.